Question

In: Physics

You exert a constant force of 20N up the slope on a 20kg block sitting on...

You exert a constant force of 20N up the slope on a 20kg block sitting on a slope of an angle 45 degrees with a coefficient of static friction of .3 and a coefficient of kinetic friction or .15. Will the block move? If so, what will it's acceleration be once it's moving?

Expert Solution

Applied force F = 20 N

Mass of the block m = 20 kg

Angle of slope = 45 ^o

coefficient of static friction = 0.3

coefficient of kinetic friction ' = 0.15

Static Frictional force f = mg cos

= 0.3 x20 x9.8 x cos 45

= 41.57 N

f is greaterthan applied force F.So, the block doesnot move in upward direction of the slope.

----------------------------------------------------------

When the block is sitting on the top of the slope then it moves in downward direction.

Force act in downward direction = mg sin

= 20 x9.8 xsin 45

= 138.6 N

Net force in downward direction F ' = mg sin -F - ( ' mg cos )

Where ' mg cos = kinetic frictional force

So, F ' = 138.6 -20 -(0.15 x20 x9.8x cos 45)

=118.6 - 20.78

= 97.82 N

Accleration in downward direction a = F ' / m

= 97.82 / 20

= 4.89 m/s ²

. Will the block move? If so, what will it's acceleration be once it's moving

genius_generous answered 1 year ago

A 13.0-lb block rests on the floor. (a) What force does the floor exert on the...

A 13.0-lb block rests on the floor. (a) What force does the floor exert on the block? magnitude lb direction ---Select--- upward downward The floor does not exert force on the block. (b) If a rope is tied to the block and run vertically over a pulley, and the other end is attached to a free-hanging 10.5-lb weight, what is the force exerted by the floor on the 13.0-lb block? magnitude lb direction ---Select--- upward downward The floor does not...

In this problem you will determine the amount of force a rider needs to exert on...

In this problem you will determine the amount of force a rider needs to exert on a bicycle pedal to accelerate at a rate of 1.0 m/s^2. (c) Now consider the system consisting of the rear wheel. The system includes the sprocket (gear wheel) attached to it. Assume that the rear sprocket has a radius of 2.5 cm and neglible mass compared to the wheel. Assume that the rear wheel has the same mass, radius, and moment of inertia as...

This force can either push the block upward at a constant velocity or allow it to...

This force can either push the block upward at a constant velocity or allow it to slide downward at a constant velocity. The magnitude of the force is different in the two cases, while the directional angle θ is the same. Kinetic friction exists between the block and the wall, and the coefficient of kinetic friction is 0.310. The weight of the block is 55.0 N, and the directional angle for the force Upper F Overscript right-arrow EndScripts is θ...

SHOW WORK: You drive your car up a constant slope for 21200 feet. In the process,...

SHOW WORK: You drive your car up a constant slope for 21200 feet. In the process, you gain 1320 feet of vertical elevation. What is the angle of this slope?

A frictionless block of mass 1.55 kgkg is attached to an ideal spring with force constant...

A frictionless block of mass 1.55 kgkg is attached to an ideal spring with force constant 350 N/m . At t=0 the spring is neither stretched nor compressed and the block is moving in the negative direction at a speed of 12.9 m/s . a)Find the amplitude. b)Find the phase angle. c)Write an equation for the position as a function of time. a)x=(−x=(−0.858 mm )sin(()sin((15.0 rad/srad/s )t))t) b)x=(−x=(−0.858 mm )cos(()cos((15.0 rad/srad/s )t))t) c)x=(−x=(−15.0m)sin((m)sin((0.858rad/s)t)rad/s)t) d)x=(−x=(−15.0m)cos((m)cos((0.858rad/s)t)rad/s)t)

How much force could you exert on a large crate if you wanted to get it...

How much force could you exert on a large crate if you wanted to get it moving? One thing the answer depends on is whether you can keep your footing. a) Imagine someone on level ground, pushing horizontally against a crate, with enough effort that their feet are about to start slipping. Nevertheless, the crate hasn't started moving. What type of force is the crate exerting on the person pushing on it, and how does the magnitude of this force...

9.) A 19.6 kg block is dragged over a rough, horizontal surface by a constant force...

9.) A 19.6 kg block is dragged over a rough, horizontal surface by a constant force of 183 N acting at an angle of angle 30.5 ◦ above the horizontal. The block is displaced 97.1 m and the coefficient of kinetic friction is 0.121. a. Find the work done by the normal force. Answer in units of J. b. What is the net work done on the block? Answer in units of J.

A 15 kg block is dragged over a rough, hor- izontal surface by a constant force...

A 15 kg block is dragged over a rough, hor- izontal surface by a constant force of 107 N acting at an angle of angle 31.9◦ above the horizontal. The block is displaced 59 m and the coefficient of kinetic friction is 0.189. Find the work done by the 107 N force. The 2 003 (part 2 of 5) 10.0 points Find the magnitude of the work done by the force of friction. Answer in units of J. 004 (part...

A force of constant magnitude pushes a box up a vertical surface, as shown in the...

A force of constant magnitude pushes a box up a vertical surface, as shown in the figure. The box moves at a constant speed. If the mass of the box is 4.0 kg, and it is pushed 2.2 m vertically upward, the coefficient of friction is 0.35, and the angle θ is 37°. What is the work done by the force, F? Use g = 10 m/s2.

A block of mass 5 kg is sitting on a frictionless surface. The block initially has...

A block of mass 5 kg is sitting on a frictionless surface. The block initially has a velocity of 3 m/s. A force of 9 N is applied for 2 s. What is the Initial momentum of the block? kg m/s Tries 0/2 What is the Initial Kinetic Energy of the block? J Tries 0/2 What is the change in momentum of the block? Kg m/s Tries 0/2 What is the final momentum of the block? kg m/s Tries 0/2...