In: Physics
a knight is trying to scale the castle wall using a ladder the mass of the knight is 73.1 kg the ladder is 2.50m long and has a mass of 8.50 kg the wall is frictionless but the coefficient of static friction between ladder and the ground is 0.250 the ladder makes an angle of 53.1 degrees with the horizontal when placed against the castle wall how far up the ladder can the knight wall before the ladder slips what is the magnitude of the force of the wall on the ladder what is the magnitude of the force of the ground on the ladder
Force of the wall on ladder is S
Force of the ground on ladder is R
the frictional force is and coefficient of static friction
mass of knight = 73.1 kg
mass of ladder = 8.50 kg length of ladder = 2.50 m
let the knight is at a distance l from the ground on the ladder. Since the knight is about to slip the wall
we consider horizontal and vertical forces
Horizontally : -----> S = (0.25) 81.6g
Vertically: R - 8.50 g - 73.1 g = 0 ---> R = 81.6g ( g is acceleration due to gravity)
Taking moment about point where the ladder meet ground :
l = 0.783 m
the knight can climb up 0.783m the ladder on wall before the ladder slips
force of wall on ladder S = 199.92 N
force of ground on ladder R = 799.68 N