In: Statistics and Probability
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I am very lost on this. If there is an Excel formula I could use, that would help tremendously. Thank you... Create confidence intervals related to the interval and ratio-level data you collected. |
| 1. What is the best estimate of the population mean |
| 2. Develop a 95% confidence interval for the population mean. Develop a 90% confidence interval for the population mean. Develop a 98% confidence interval for the population mean. |
| 3. Interpret the confidence interval. |
| Create an individual Excel document for each of the required items. |
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APA format is not required, but solid academic writing is expected. I have all my numbers but I am very unsure of how to go about this. Is there an Excel formula to calculate this. Here are my numbers: Breakfast I came up with the mean as 4.4505 |
| $1.07 |
| $1.59 |
| $1.81 |
| $2.13 |
| $2.14 |
| $2.45 |
| $2.88 |
| $3.21 |
| $3.40 |
| $3.51 |
| $3.63 |
| $3.73 |
| $3.84 |
| $4.27 |
| $4.28 |
| $4.70 |
| $4.90 |
| $5.33 |
| $5.34 |
| $5.35 |
| $5.54 |
| $5.66 |
| $5.76 |
| $5.77 |
| $6.09 |
| $6.30 |
| $6.42 |
| $6.62 |
| $6.73 |
| $6.92 |
| $6.94 |
| $7.03 |
| $7.47 |
| $7.48 |
| $7.69 |
| $7.78 |
| $8.25 |
| $8.43 |
| $8.66 |
| $11.32 |
| $11.52 |
| $13.25 |
| $13.89 |
|
$15.95 Lunch I came up with the mean as 7.9955 |
| 2.13 |
| 2.99 |
| 4.15 |
| 4.27 |
| 4.28 |
| 4.28 |
| 4.28 |
| 4.47 |
| 5.21 |
| 5.33 |
| 5.35 |
| 5.35 |
| 5.35 |
| 5.35 |
| 5.54 |
| 5.65 |
| 5.75 |
| 5.87 |
| 6.29 |
| 6.39 |
| 6.41 |
| 6.42 |
| 6.42 |
| 6.42 |
| 6.42 |
| 6.42 |
| 6.51 |
| 6.51 |
| 6.71 |
| 7.05 |
| 7.05 |
| 7.05 |
| 7.35 |
| 7.45 |
| 7.56 |
| 7.69 |
| 7.80 |
| 7.80 |
| 8.01 |
| 8.11 |
| 8.22 |
| 8.22 |
| 8.86 |
| 8.96 |
| 9.26 |
| 9.35 |
| 9.37 |
| 9.39 |
| 9.82 |
| 11.01 |
| 11.10 |
| 11.41 |
| 11.73 |
| 12.17 |
| 13.57 |
| 15.34 |
| 15.78 |
| 16.22 |
| 18.28 |
| 22.21 |
Sol:
in excel
install analysis toolpak an then go to
Data >data analysis>Descriptive statistcs
you will get
| Breakfast | lunch | ||
| Mean | 6.068864 | Mean | 7.995167 |
| Standard Error | 0.495797 | Standard Error | 0.484616 |
| Median | 5.71 | Median | 7.05 |
| Mode | #N/A | Mode | 6.42 |
| Standard Deviation | 3.288743 | Standard Deviation | 3.753818 |
| Sample Variance | 10.81583 | Sample Variance | 14.09115 |
| Kurtosis | 1.370727 | Kurtosis | 3.306239 |
| Skewness | 1.075678 | Skewness | 1.642936 |
| Range | 14.88 | Range | 20.08 |
| Minimum | 1.07 | Minimum | 2.13 |
| Maximum | 15.95 | Maximum | 22.21 |
| Sum | 267.03 | Sum | 479.71 |
| Count | 44 | Count | 60 |
From the above table take .,mean,standard deviaton,sample size.
use confidence.t to get the margin of error
and
90% confidence interval as sample mean-margin of error,sample mean+margin of error
sample mean for breakfast is 6.068864
sample mean for lumch is 7.995167
to get the confidence intervals for breakfast in excel
margin of error
=CONFIDENCE.T(0.1;3.288743;44)
=0.833469243
| sample mean=xbar | 6.068864 |
| margin of error | 0.833469 |
| 90% lower limit of mean for breakfast | 5.235394 |
| 90% upper limit of man for breakfast | 6.902333 |
margin f error for 95%==CONFIDENCE.T(0.05;3.288743;44)=0.999869
| sample mean=xbar | 6.068864 | |
| margin of error | 0.999869 | |
| 95% lower limit of mean for breakfast | 5.068994 | |
| 95% upper limit of man for breakfast | 7.068733 |
similarly 98% margin of error as
=CONFIDENCE.T(0.02;3.288743;44)
=1.197968748
| sample mean=xbar | 6.068864 |
| margin of error | 1.197969 |
| 98% lower limit of mean for breakfast | 4.870895 |
| 98% upper limit of man for breakfast | 7.266832 |