In: Accounting
Brief Exercise 8-08
Compute interest and find the maturity date for the following notes. (Round answers to 0 decimal places, e.g. 825. Use 360 days for calculation.)
|
Date of Note |
Principal |
Interest Rate (%) |
Terms |
|||||
|---|---|---|---|---|---|---|---|---|
|
(a) |
June 10 | $84,000 | 8% | 60 days | ||||
|
(b) |
July 14 | $52,400 | 9% | 90 days | ||||
|
(c) |
April 27 | $12,000 | 10% | 75 days |
|
Interest |
Maturity Date |
|||
|---|---|---|---|---|
|
(a) |
$enter the amount of interest in dollars rounded to 0 decimal places | select a maturity date
June 30July 1July 10July 11July 12July 31August 1August 8August 9August 10September 30October 1October 11October 12October 13 |
||
|
(b) |
$enter the amount of interest in dollars rounded to 0 decimal places | select a maturity date
June 30July 1July 10July 11July 12July 31August 1August 8August 9August 10September 30October 1October 11October 12October 13 |
||
|
(c) |
$enter the amount of interest in dollars rounded to 0 decimal places | select a maturity date
June 30July 1July 10July 11July 12July 31August 1August 8August 9August 10September 30October 1October 11October 12October 13 |
| Solution: A | |||
| CALCULATION OF INTEREST EXPENSES AND MATURITY DATA FOR JUNE 10 NOTE | |||
| Par Value of note | $ 84,000 | ||
| Interet Rate | 8% | ||
| Interest Amount for one year = | $ 6,720 | ||
| Interest for 60 Days = $ 6,720 X 60 / 360 = | $ 1,120 | ||
| Maturity Date = | |||
| Balance Days in June = | 20 | Days | |
| Days in July | 31 | Days | |
| Days in August | 9 | Days | |
| Answer = Interest = $ 1,120 and date of Maturity = 9th August | |||
| Solution: B | |||
| CALCULATION OF INTEREST EXPENSES AND MATURITY DATA FOR JULY 14 | |||
| Par Value of note | $ 52,400 | ||
| Interet Rate | 9% | ||
| Interest Amount for one year = | $ 4,716 | ||
| Interest for 90 Days = $ 4,716 X 90 / 360 = | $ 1,179 | ||
| Maturity Date = | |||
| Balance Days in July = | 17 | Days | |
| Days in August | 31 | Days | |
| Days in September | 30 | Days | |
| Days in October | 12 | Days | |
| Answer = Interest = $ 1,179 and date of Maturity = 12th October | |||
| Solution: C | |||
| CALCULATION OF INTEREST EXPENSES AND MATURITY DATA FOR APRIL 27 NOTE | |||
| Par Value of note | $ 12,000 | ||
| Interet Rate | 10% | ||
| Interest Amount for one year = | $ 1,200 | ||
| Interest for 75 Days = $ 1,200 X 75 / 360 = | $ 250 | ||
| Maturity Date = | |||
| Balance Days in April | 4 | Days | |
| Days in May | 31 | Days | |
| Days in June | 30 | Days | |
| Days in July | 10 | Days | |
| Answer = Interest = $ 250 and date of Maturity = 10 th of July | |||