In: Chemistry
If 2 L, 4 L and 6 L of three separate solutions of concentrations 1 M, 2 M and 3 M respectively, are mixed together then what is the concentration of the resultant mixture?
Explanation :
Given :
V1 = 2 L
V2 = 4 L
V3 = 6L
M1 = 1 M
M2 = 2 M
M3 = 3 M
Resultant concentration, Mr
Mr=Resultant moles/Resultant volume
Resultant moles = Conc.n × Volume
Resultant concentration, Mr
Mr = (M1V1 + M2V2 + M3V3)/(V1 + V2 + V3)
Mr = (2×1 + 4×2 + 6×3)/(2 + 4 + 6)
= 2.333 M.
Concentration of resultant mixture is 2.333 M.
Concentration of resultant mixture is 2.333 M