If 2 L, 4 L and 6 L of three separate solutions of concentrations 1 M, 2 M and 3 M, respectively, are mixed together then what is the concentration of the resultant mixture?

If 2 L, 4 L and 6 L of three separate solutions of concentrations 1 M, 2 M and 3 M respectively, are mixed together then what is the concentration of the resultant mixture?

Solutions

Expert Solution

Explanation :

Given :

V1 = 2 L

V2 = 4 L

V3 = 6L

M1 = 1 M

M2 = 2 M

M3 = 3 M

Resultant concentration, Mr

Mr=Resultant moles/Resultant volume

Resultant moles = Conc.n × Volume

Resultant concentration, Mr

Mr = (M1V1 + M2V2 + M3V3)/(V1 + V2 + V3)

Mr = (2×1 + 4×2 + 6×3)/(2 + 4 + 6)

= 2.333 M.

Concentration of resultant mixture is 2.333 M.

Concentration of resultant mixture is 2.333 M

Rakesh answered 1 year ago

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