Question

There are a number of steps involved in determining the empirical formula of a compound. You will need to demonstrate that you can complete all of these steps as you determine the empirical formula of a compound composed of phosphorus and chlorine that is 14.87 % P by mass. Complete your calculations based on 100 g of this compound. Enter all calculated values in 4 significant figures followed by one space and the appropriate unit. Use g for grams and mole for moles. Do not use scientific notation.

Determine the mass in grams of chlorine present in the sample. Answer

Determine the number of moles of phosphorus in the sample. Answer

Determine the number of moles of chlorine in the sample.
Answer

The moles of (Answer Cl or P) represents the smaller mole value.

Write the empirical formula of the compound. You will not be able to show subscript values correctly. For example, H2O would be recorded for water.
Answer

Answer 1

A similar question is solved below, but with different values. Please workout using your figures. Hope this helps you. Please rate me.

There are a number of steps involved in determining the empirical formula of a compound. You will need to demonstrate that you can complete all of these steps as you determine the empirical formula of a compound composed of phosphorus and chlorine that is 22.55 % P by mass. Complete your calculations based on 100 g of this compound. Enter all calculated values in 4 significant figures followed by one space and the appropriate unit. Use g for grams and mole for moles. Do not use scientific notation?

Determine the mass in grams of chlorine present in the sample

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Determine the number of moles of phosphorus in the sample. Answer
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Determine the number of moles of chlorine in the sample.
Answer____________

The moles of AnswerPCl represents the smaller mole value.
__________-
Write the empirical formula of the compound. You will not be able to show subscript values correctly. For example, H2O would be recorded for water____________-

step one

compound weight = 100g

contain only P(22.5%) and Cl(77.5%)   P = 22.5g = 22.5/31 =0.72mole Cl = 77.5g =77.5/35.4 = 2.2

step two

P(0.72) Cl(2.2)    = P Cl(2.2/0.72) =     PCl₃ is the emperical formulae and molecular formulae

1) mass in gram of Cl =77.5g

2) number of mole of phospherous = 0.72mole

3) number of mole of Cl = 2.2 mole

4) smaller mole value = P Cl(2.2/0.72) = PCl3

5) emperical formulae = PCl3