Question

In: Chemistry

A chemistry handbook lists the solubility of sodium iodide (NaL) as 184 g per 100 ml...

A chemistry handbook lists the solubility of sodium iodide (NaL) as 184 g per 100 ml of water at 25^o C.

What would be the percent by mass of a NaL solution prepared by dissolving 95.0 g NaL in 450 g water?

Expert Solution

Answer – We are given, solubility of sodium iodide (NaI) = 184 g per 100 mL

We are asking for the percent by mass of a NaI solution prepared by dissolving 95.0 g NaI in 450 g water

We know,

Water density = 1g/mL

Means 450 g = 450 mL

We also given solubility of sodium iodide

100 mL = 184 g

So, 450 mL = ?

= 828 g of NaI

Means in the 450 mL water there are 828 g of NaI is soluble and we are given 95.0 g of NaI, means all NaI gets dissolved in the solution

So total mass of solution = 450 g + 95 g

= 545 g

Percent by mass of a NaI solution = mass of NaI in solution / total mass of solution *100%

= 95 g / 545 g * 100 %

= 17.4 %

queen_honey_blossom answered 1 year ago

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