In: Statistics and Probability
If the average survival of a red cell in the human body is 120 days with a standard deviation of 8 days, what is the probability for each of the following events? Assume a normal distribution,
a. | A red cell surviving more than 134 days? | |
b. | A red cell that survives less than 110 days? | |
c. | A red cell surviving between 108 and 122 days? | |
Solution :
Given that ,
a.
P(x > 134) = 1 - P(x < 134)
= 1 - P[(x - ) / < (134 - 120) / 8)
= 1 - P(z < 1.75)
= 1 - 0.9599
= 0.0401
Probability = 0.0401
b.
P(x < 110) = P[(x - ) / < (110 - 120) / 8]
= P(z < -1.25)
= 0.1056
Probability = 0.1056
c.
P(108 < x < 122) = P[(108 - 120)/ 8) < (x - ) / < (122 - 120) / 8) ]
= P(-1.5 < z < 0.25)
= P(z < 0.25) - P(z < -1.5)
= 0.5987 - 0.0668
= 0.5319
Probability = 0.5319