Question

In: Statistics and Probability

It is believed that the majority of Americans do not eat any lunch. A 95% confidence...

It is believed that the majority of Americans do not eat any lunch. A 95% confidence interval for the population proportion of Americans who do not eat any lunch is between .475 and .535. What was the sample size?

Solutions

Expert Solution

Solution :

Point estimate = = (Lower confidence interval + Upper confidence interval ) / 2

Point estimate = = (0.475+0.535) / 2=0.505

Margin of error = E = Upper confidence interval - = 0.535-0.505=0.03

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96 ( Using z table )

Sample size = n = (Z/2 / E)2 * * (1 - )

= (1.96 / 0.03)2 * 0.505 * 0.495

= 1067.00

Sample size =1067


Related Solutions

A newsgroup is interested in constructing a 95% confidence interval for the proportion of all Americans...
A newsgroup is interested in constructing a 95% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 537 randomly selected Americans surveyed, 368 were in favor of the initiative. a. With 95% confidence the proportion of all Americans who favor the new Green initiative is between and . b. If many groups of 537 randomly selected Americans were surveyed, then a different confidence interval would be produced from each group....
A newsgroup is interested in constructing a 95% confidence interval for the proportion of all Americans...
A newsgroup is interested in constructing a 95% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 555 randomly selected Americans surveyed, 385 were in favor of the initiative. Round answers to 2 decimal places where possible. a. With 95% confidence the proportion of all Americans who favor the new Green initiative is between and . b. If many groups of 555 randomly selected Americans were surveyed, then a different...
A newsgroup is interested in constructing a 95% confidence interval for the proportion of all Americans...
A newsgroup is interested in constructing a 95% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 539 randomly selected Americans surveyed, 442 were in favor of the initiative. Round answers to 4 decimal places where possible. a. With 95% confidence the proportion of all Americans who favor the new Green initiative is between ____and _____ . b. If many groups of 539 randomly selected Americans were surveyed, then a...
A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of adults who eat fast...
A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of adults who eat fast food four to six times per week. Her estimate must be accurate within 5​% of the population proportion. ​(a) No preliminary estimate is available. Find the minimum sample size needed. ​(b) Find the minimum sample size​ needed, using a prior study that found that 26​% of the respondents said they eat fast food four to six times per week. ​(c) Compare the results from...
A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of adults who eat fast...
A researcher wishes to​ estimate, with 95​% ​confidence, the population proportion of adults who eat fast food four to six times per week. Her estimate must be accurate within 1​% of the population proportion. ​(a) No preliminary estimate is available. Find the minimum sample size needed. ​(b) Find the minimum sample size​ needed, using a prior study that found that 40​% of the respondents said they eat fast food four to six times per week. ​(c) Compare the results from...
A majority of Americans and a strong majority of young Americans (those below 30) now support...
A majority of Americans and a strong majority of young Americans (those below 30) now support same-sex marriages. What are some cultural and structural changes that have led to this increase in support for marriage equality over the past decade?
You want to create a 95% confidence interval to estimate the proportion of Americans that like...
You want to create a 95% confidence interval to estimate the proportion of Americans that like beets. What is the minimum sample size you need to guarantee a margin of error no larger than .05?
A 95% confidence interval for the proportion of Americans under the age of thirty who skip...
A 95% confidence interval for the proportion of Americans under the age of thirty who skip break-fast is found to be (0.2025, 0.2795). For each choice below, answer True or False: a. T or F There is a 95% probability that the true proportion of Americans under the age of thirty who skip breakfast is between 20.25% and 27.95%. b. T or F If this study were to be repeated many times with samples of the same size, then 95%...
Give and interpret the 95% confidence intervals for males and a second 95% confidence interval for...
Give and interpret the 95% confidence intervals for males and a second 95% confidence interval for females on the SLEEP variable. Which is wider and why? Known values for Male and Female: Males: Sample Size = 17; Sample Mean = 7.765; Standard Deviation = 1.855 Females: Sample Size = 18; Sample Mean = 7.667; Standard Deviation = 1.879 Using t-distribution considering sample sizes (Male/Female count) are less than 30
95% Confidence Interval: 86.19 ± 0.364 (85.8 to 86.6) "With 95% confidence the population mean is...
95% Confidence Interval: 86.19 ± 0.364 (85.8 to 86.6) "With 95% confidence the population mean is between 85.8 and 86.6, based on 33945 samples." Short Styles: 86.19 (95% CI 85.8 to 86.6) 86.19, 95% CI [85.8, 86.6] Margin of Error: 0.364 What is the impact of your margin of error on your findings? Explain. Is there enough evidence to reject the null hypotheses, explain in plain English?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT