In: Mechanical Engineering
CHOCHITO, S.A homemade sweets factory wants to determine the normal time and standard time for packaging and packaging of its variety of products. The following table contains the data about a recent study, regarding the measurement of the elements to be carried out. A measurement is considered incorrect if it has a variability greater than +/- 10%, therefore it must be eliminated from the calculation. Knowing that the company grants its workers 30 minutes for the necessary delay and fatigue:
Work elements Cycles in minutes R
1. Take a container | 1.7 | 1.8 | 2.2 | 1.7 | 2.3 | 1.9 | 2.1 | 1.8 | 2.2 | 1.7 | 130% |
2. Fill the container | 4.3 | 5.7 | 4.4 | 5.6 | 4.6 | 5.5 | 4.6 | 5.4 | 4.7 | 5.3 | 120% |
3. Cover the container | 3.4 | 4.6 | 3.5 | 4.5 | 3.6 | 4.4 | 3.7 | 4.3 | 3.8 | 4.2 | 110% |
4. Place the label | 1.9 | 2.1 | 1.8 | 2.2 | 1.7 | 2.3 | 1.8 | 2.2 | 1.7 | 2.3 | 120% |
5. Place 24 containers per box | 2.3 | 1.8 | 2.2 | 1.7 | 2.3 | 1.9 | 2.1 | 1.8 | 2.2 | 1.7 | 140% |
6. Stack the full boxes |
7 | 9 | 6.8 |
9.2 |
6.9 | 9.1 | 7.1 | 8.9 | 7.2 | 8.8 | 120% |
Calculate:
a. Normal time and standard time
b. Calculate the number of boxes per worker
Assumptions
Company runs for 8 hours per day (i.e 1 shift per day) excluding Lunch Break
Allowance (TA) offered by company is 30 minutes per shift (Personal allowance (PA) + Fatigue Allowance (FA))
Solution
Let Available Time (AT) = 8 hours per day
Total Allowance (TA) per worker = 30 mins per day
Work Element is denoted by WE
Step 1:
Average Time for WE1 =
=
=
TWE1 = 1.94 min
Similarly,
TWE2 = 5.01 min
TWE3 = 4 min
TWE4 = 2 min
TWE5 = 2 min
TWE6 = 8 min
Step 2:
Elimination of Variability ± 10%
10% of TWE1 = 0.19
therefore, observations only in the range of 1.94 ± 0.19 (1.7 min to 2.1)
Now TWE1 =
TWE1 = 1.9 min
repeating the same procedure for other work elements,
the average time turns out to be the following
Take a Container | Fill the Container | Cover the Container | Place the Label | Place 24 Containers per box | Stack the full Boxes |
X | X | X | 1.9 | X | X |
1.8 | 5.7 | X | 2.1 | 1.8 | X |
X | X | X | 1.8 | 2.2 | X |
X | 5.6 | X | 2.2 | X | X |
X | X | 3.6 | X | X | X |
X | 5.5 | 4.4 | X | 1.9 | X |
2.1 | X | 3.7 | 1.8 | 2.1 | X |
1.8 | 5.4 | 4.3 | 2.2 | 1.8 | 8.9 |
X | X | 3.8 | X | 2.2 | 7.2 |
X | 5.3 | 4.2 | X | X | 8.8 |
TWE1 = 1.9 min | TWE2 = 5.5 min | TWE2 = 4 min | TWE2 = 2 min | TWE2 = 2 min | TWE2 = 8.3 min |
Nominal Time (NT) = Observed Time (TWE) X Rating Factor (R) / 100
NT1 = TWE1 * 130 / 100
NT1 = 2.47 min
Similarly
NT2 = 6.6 min
NT3 = 4.4 min
NT4 = 2.4 min
NT5 = 2.8 min
NT6 = 9.96 min
Step 3:
Standard Time (ST) Calculation
Standard Time (ST) =
Allowance Factor = Total Allowance time / Total working time
= 30 / (8 * 60)
= 0.0625
ST for container process =
ST = 16.92 min
Standard Time for complete Cntainer process is 16.92 mins
Standard Time for Packing Box is 2.98 mins
STandard Time Stacking the Box is 10.62 mins