Question

In: Chemistry

A 5.314 g sample of a solid, weak, monoprotic acid is used to make a 100.0...

A 5.314 g sample of a solid, weak, monoprotic acid is used to make a 100.0 mL solution. 30.00 mL of the resulting acid solution is then titrated with 0.09533 M NaOH. The pH after the addition of 17.00 mL of the base is 5.45, and the endpoint is reached after the addition of 45.61 mL of the base.

(a) How many moles of acid were present in the 30.00 mL sample?
mol

(b) What is the molar mass of the acid?
g/mol

(c) What is the pKa of the acid?

Solutions

Expert Solution


Related Solutions

A 5.079 g sample of a solid, weak, monoprotic acid is used to make a 100.0...
A 5.079 g sample of a solid, weak, monoprotic acid is used to make a 100.0 mL solution. 26.00 mL of the resulting acid solution is then titrated with 0.09454 M NaOH. The pH after the addition of 18.00 mL of the base is 5.54, and the endpoint is reached after the addition of 47.60 mL of the base. Please see Titration to Determine Molecular Weight for assistance. (a) How many moles of acid were present in the 26.00 mL...
A 1.491-g sample of a solid, weak, monoprotic acid is used to make 100.0 mL of...
A 1.491-g sample of a solid, weak, monoprotic acid is used to make 100.0 mL of solution. 35.0 mL of this solution was titrated with 0.08730-M NaOH. The pH after the addition of 19.69 mL of base was 4.56, and the equivalence point was reached with the addition of 39.30 mL of base. a) How many millimoles of acid are in the original solid sample? Hint: Don't forget the dilution. mmol acid b) What is the molar mass of the...
A 6.053-g sample of a solid, weak, monoprotic acid is used to make 100.0 mL of...
A 6.053-g sample of a solid, weak, monoprotic acid is used to make 100.0 mL of solution. 15.0 mL of this solution was titrated with 0.08386-M NaOH. The pH after the addition of 23.33 mL of base was 3.90, and the equivalence point was reached with the addition of 43.69 mL of base. a) How many millimoles of acid are in the original solid sample? Hint: Don't forget the dilution. Correct: Your answer is correct. mmol acid b) What is...
A chemist synthesized a monoprotic weak acid, (HA) and 2.00 mmol of the solid acid is...
A chemist synthesized a monoprotic weak acid, (HA) and 2.00 mmol of the solid acid is dissolved in 100.0 ml of water. The acid is titrated with 20.0 ml of 0.0500 M NaOH. If the final solution has a pH of 6.00, what's the Ka of the acid?
The pKa of formic acid is 3.74, a monoprotic weak acid. A 1.0 L sample of...
The pKa of formic acid is 3.74, a monoprotic weak acid. A 1.0 L sample of a buffer with a pH of 4.5 is combined with .09 mol of NaOH. What is the new pH of the solution? The ratio of HCOO- to H+ is .86 M to .15 M.
If the Ka of a monoprotic weak acid is 8.2
If the Ka of a monoprotic weak acid is 8.2
A professor titrated 0.47 g of an unknown monoprotic weak acid with 0.0973 M NaOH. The...
A professor titrated 0.47 g of an unknown monoprotic weak acid with 0.0973 M NaOH. The titration data is below. a) Calculate # of moles of NaOH required to reach the equivalence point (endpoint). b) Determine # of moles of acid titrated. c) Calculate Molar mass of unknown acid. d) determine the pKa of the unknown acid. e) Calculate the Ka of the unknown acid. Volume NaOH (mL) pH 0.00 2.73 2.00 3.30 4.00 3.64 6.00 3.86 8.00 4.03 10.00...
1) The Ka of a monoprotic weak acid is 2.47
1) The Ka of a monoprotic weak acid is 2.47
1) If the Ka of a monoprotic weak acid is 2.1
1) If the Ka of a monoprotic weak acid is 2.1
A.) Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize...
A.) Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP. What volume of a 0.117 M potassium hydroxide solution is needed to exactly neutralize 0.692 grams of KHP ? ANSWER: mL potassium hydroxide B.) Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT