Question

C++ questions, please make sure to dividet he program into functions which perform each major task,

0. A leap year is defined as any calendar year which meets the following criteria:

   • If the year is not divisible by 4, it is a common year

   • If the year is not divisible by 100, it is a leap year

   • If the year is not divisible by 400, it is a common year

   • Otherwise it is a leap year
     For your program you will take in three integers from the user:

   • A four digit year

   • The day of the month (between 1 and 31)

   • The month (between 1 and 12, 1 representing January and 12 representing December)

     Your program will output whether or not the date entered is a valid calendar date. Be sure to divide your program into functions which perform each major task.

     Hint: There are 30 days in September, April, June and November. If the year is a leap year, there are 29 days in February. If the year is a common year there are 28 days in February. All other months have 31 days. Some examples to help you verify leap year calculation:

1. Condition	Result	Examples
   Not divisible by 4	Not a leap year	2009, 2010, 2011
   Divisible by 4	Leap year	2008, 2012, 2016
   Divisible by 100	Not a leap year	1800, 1900, 2100
   Divisible by 400	Leap year	2000, 2400

Answer 1

#include <iostream>
using namespace std;

void leapyear(int year) {
    //Giving conditions for each year dividing by 4,100 and 400
    if (year % 4 == 0)
    {
        if (year % 100 == 0)
        {
            if (year % 400 == 0)
                cout << year << " is a leap year.";
            else
                cout << year << " is not a leap year.";
        }
        else
            cout << year << " is a leap year.";
    }
    else
        cout << year << " is not a leap year.";
}

int main()
{
    int year;
    //Taking user input
    cout << "Enter a year: ";
    cin >> year;
    //Calling leap year function
    leapyear(year);
    return 0;
}

Sample input and output:

Enter a year: 2010
2010 is not a leap year.

Enter a year: 2016
2016 is a leap year.

#include <iostream>
using namespace std;

void leapyear(int year) {
    //Giving conditions for each year dividing by 4,100 and 400
    if (year % 4 == 0)
    {
        cout << year << " is divided by 4.\n";
        if (year % 100 == 0)
        {
            cout << year << " is divided by 100.\n";
            if (year % 400 == 0) {
                cout << year << " is divided by 400.\n";
                cout << year << " is a leap year.";
            }
            else
                cout << year << " is not a leap year.";
        }
        else
            cout << year << " is a leap year.";
    }
    else {
        cout << "Not divisible by 4.\n";
        cout << year << " is not a leap year.";
    }
}

int main()
{
    int year;
    //Taking user input
    cout << "Enter a year: ";
    cin >> year;
    //Calling leap year function
    leapyear(year);
    return 0;
}

Sample input and output:

Enter a year: 2009
Not divisible by 4.
2009 is not a leap year.

Enter a year: 1800
1800 is divided by 4.
1800 is divided by 100.
1800 is not a leap year.