Question

In: Chemistry

An aqueous solution of 0.0190g of a protein in 10.0 mL of water at 20.0 ̊C...

An aqueous solution of 0.0190g of a protein in 10.0 mL of water at 20.0 ̊C shows a 5.22 cm rise inthe apparatus shown in the figure. Assume the density of the solution

to be 0.998g/mL, andthe density of mercury to be 13.6 g/cm3. What is the molar mass of the protein?

Solutions

Expert Solution

pressure of system = 5.22 x 10/760 = 0.07 atm

So,

molarity of solution = p/iRT

                               = 0.07/1 x 0.08205 x (273 + 20)

                               = 0.003 M

molar mass of protein = 0.0190 g/0.003 M x 0.01 L

                                    = 633.33 g/mol


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