In: Chemistry
An aqueous solution of 0.0190g of a protein in 10.0 mL of water at 20.0 ̊C shows a 5.22 cm rise inthe apparatus shown in the figure. Assume the density of the solution
to be 0.998g/mL, andthe density of mercury to be 13.6 g/cm3. What is the molar mass of the protein?
pressure of system = 5.22 x 10/760 = 0.07 atm
So,
molarity of solution = p/iRT
= 0.07/1 x 0.08205 x (273 + 20)
= 0.003 M
molar mass of protein = 0.0190 g/0.003 M x 0.01 L
= 633.33 g/mol