In: Statistics and Probability
You suspect that an unscrupulous employee at a casino has tampered with a die; that is, he is using a loaded die. In order to test this claim, you roll the die 200 times and obtain the following frequencies: (You may find it useful to reference the appropriate table: chi-square table or F table) Click here for the Excel Data File Category 1 2 3 4 5 6 Frequency 40 35 33 30 33 29 a. Choose the appropriate alternative hypothesis to test if the population proportions differ. All population proportions differ from 1/6. Not all population proportions are equal to 1/6.
b. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.)
(a)
H0:Null Hypothesis: All population proportions are equal to 1/6. (Claim)
HA:Alternative Hypothesis: Not all population proportions are equal to 1/6.
(b)
Test Statistic () is calculated as follows:
Observed (O) | Expected (E) | (O - E)2?E |
40 | 200/6 = 33.3333 | (40-33.3333)2/33.3333=1.3333 |
35 | 200/6 = 33.3333 | (35-33.3333)2/33.3333=0.0833 |
33 | 200/6 = 33.3333 | (33-33.3333)2/33.3333=0.0033 |
30 | 200/6 = 33.3333 | (30-33.3333)2/33.3333=0.3333 |
33 | 200/6 = 33.3333 | (33-33.3333)2/33.3333=0.0033 |
29 | 200/6 = 33.3333 | (29-33.3333)2/33.3333=0.5633 |
Total = Test Statistic () = | 2.320 |
the value of the test statistic. = 2.320
(c)
df = 6 - 1= 5
Take = 0.05
From Table, critical value of = 11.07
Since calculated value of = 2.320 is less than critical value of = 11.07, the difference is not significant. Fail to reject null hypothesis.
Conclusion:
The data support the claim that all population proportions are
equal to 1/6.