Question

Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the given sample data. An experiment was conducted to determine whether a deficiency of carbon dioxide in the soil affects the phenotype of peas. Listed below are the phenotype codes where 1 equals smooth dash yellow​, 2 equals smooth dash green​, 3 equals wrinkled dash yellow​, and 4 equals wrinkled dash green. Do the results make​ sense? 2 2 1 4 3 1 4 1 4 2 1 1 2 1 ​(a) The mean phenotype code is nothing. ​(Round to the nearest tenth as​ needed.) ​(b) The median phenotype code is nothing. ​(Type an integer or a​ decimal.) ​(c) Select the correct choice below and fill in any answer boxes within your choice. A. The mode phenotype code is nothing. ​(Use a comma to separate answers as​ needed.) B. There is no mode. ​(d) The midrange of the phenotype codes is nothing. ​(Type an integer or a​ decimal.) Do the measures of center make​ sense? A. All the

measures of center make sense since the data is numerical. B. Only the mode makes sense since the data is nominal. C. Only the​ mean, median, and midrange make sense since the data is nominal. D. Only the​ mean, median, and mode make sense since the data is numerical.

Answer 1

a)

Mean = (2 + 2 + 1 + 4 + 3 + 1 + 4 + 1 + 4 + 2 + 1 + 1 + 2 + 1)/14
= 29/14
Mean = 2.0714

b)

The median is the middle number in a sorted list of numbers. So, to find the median, we need to place the numbers in value order and find the middle number.

Ordering the data from least to greatest, we get:

1   1   1   1   1   1   2   2   2   2   3   4   4   4   

As you can see, we do not have just one middle number but we have a pair of middle numbers, so the median is the average of these two numbers:

Median = 2+2/2 =2

c)

The mode of a set of data is the value in the set that occurs most often.

Ordering the data from least to greatest, we get:

1   1   1   1   1   1   2   2   2   2   3   4   4   4   

We see that the mode is 1 .

d)

The minimum value of a data set (Min. Value): 1

The maximum value of a data set (Max. Value): 4

Midrange = (Min. Value + Max. Value) / 2 = (1 + 4) / 2 = 2.5

Only the mode makes sense since the data is nominal.