Question

double maxArea(Rectangle a, Rectangle b, Rectangle c) {

    double width;
    double length;
    double area = 0;

    area = width * length;

    cout << "\n***maxArea called" << endl;     
    cout << "***       rectangleCount = " << Rectangle::rectangleCount << endl << endl;

  
}

Compete this code to find the maximum area of rectangle between a,b,c

Answer 1

#include <iostream>
class Rectangle{
    public:
        double width=0;
        double length=0;
        Rectangle(double length, double width){
            this->width = length;
            this->length = width;
        }
        void print(){
            std::cout<<length;
            std::cout<<width;
        }
};

double maxArea(Rectangle a, Rectangle b, Rectangle c) {

    double area_a = 0, area_b = 0, area_c = 0;
    double max_Area = 0;

    area_a = a.length * a.width;
    area_b = b.length * b.width;
    area_c = c.length * c.width;

    max_Area = area_a;
    if (area_b > max_Area) {
        max_Area = area_b;
    }
    if (area_c > max_Area) {
        max_Area = area_c;
    }

    if(area_a == max_Area)
        std::cout<<"Rectangle a has maximum area ";
    if(area_b == max_Area)
        std::cout<<"Rectangle b has maximum area ";
    if(area_c == max_Area)
        std::cout<<"Rectangle c has maximum area ";
    return max_Area;
}

int main(){
    Rectangle a (9000,20);
    Rectangle b (500,30);
    Rectangle c (40,50);
    std::cout<<maxArea(a,b,c)<<" sq unit.";
    return 0;
}