In: Statistics and Probability
The Pearson’s coefficient of correlation (r) between a patient’s systolic and diastolic heart rate values was calculated as 0.47
1. The hypotheses are
Null hypothesis H0: ρ = 0 There is not a significant linear correlation exists between a patient’s systolic and diastolic heart rate.
Alternative Hypothesis HA: ρ ≠ 0 There is a significant linear correlation between a patient’s systolic and diastolic heart rate.
coefficient of correlation r = 0.47, Number of observations (n) = 8
2. Test statistics
t = r n-2 / 1-r2
t = 0.47 * √(8-2) / √(1-(0.47)^2) = 1.3043
Test statistics t = 1.3043
This test statistics follows t distribution with n-2 df. The test is two sided.
3. We have given that two tailed t critical value at α = 0.05, n-2 = 6
tα/2 = t0.025,6 = 2.447
4. If |t|> 2.447 then we reject H0.
Since |t| = 1.3043 < 2.447 so we do not reject H0.
There is not a sufficient evidence to support the claim that there is a significant linear correlation exists between the two variables at 0.05 level of significance.