Question

In: Chemistry

A suba diver 60ft below the ocean surface inhales 50.0mL of compressed air at 3.00 atm...

A suba diver 60ft below the ocean surface inhales 50.0mL of compressed air at 3.00 atm and 241K from a scuba tank. What is the pressure of the air at 37C in the lungs where it expands to 150.mL?

Solutions

Expert Solution

Initial conditions of air:

Pressure P1 = 3.00 atm

Volume V1 = 50.0 mL

Temperature T1 = 241 K

Final conditions of air:

Pressure P2 = ?

Volume V2 = 150 mL

Temperature T2 = 37 oC = 37 + 273 K = 310 K

We know that P1V1/T1 = P2V2/T2

                       P2 = (P1V1/T1) (T2/V2)

                           = ( 3.00 atm x 50.0 mL/ 241 K ) ( 310 K/ 150 mL)

                          = 1.286 atm

                     P2 = 1.286 atm

Therefore,

Final pressure of the air = 1.286 atm


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