Question

Experiment    [A]      [B]   Initial Rate (M/s)

        1         0.20    0.50        0.32

        2         0.60    0.50        2.88

        3         0.20    0.25        0.040

Part A: Use the following data to determine the order with respect to reactant A in the reaction 3 A + 4 B → 2 C

Part B: Use the following data to determine the order with respect to reactant B in the reaction 3 A + 4 B → 2 C

Answer 1

Ans:- The given reaction is A+4B -> 2C

Let

Rate = K[A]^x[B]^y

Let us write the given data in tabular form

Experiment	[A]	[B]	initial rate
1	0.20	0.50	0.32
2	0.60	0.50	2.88
3	0.20	0.25	0.040

For 1st experiment

R₁ =K[0.20]^x[0.50]^y

0.32 =K[0.20]^x[0.50]^y be equation 1

For 2nd experiment

R₂ = K[0.60]^x[0.50]^y

2.88 = K[0.60]^x[0.50]^y be equation 2

For 3rd experiment

R₃ =K[0.20]^x[0.25]^y

0.040 =K[0.20]^x[0.25]^y be equation 3

Now Equation 2 divided by equation 1

we get

2.88 /0.32 = [0.60/0.20]^x

9=(3)^x

(3)² =(3)^x

x=2

Part A) Therefore order with respect to reactant A = 2

Again ,

Equation 1 divided by equation 3

we get

0.32/0.040 =[0.50/0.25]^y

8=(2)^y

(2)³ = (2)^y

y=3

Part B) Therefore order with respect to reactant B = 3