given an aqueous solution of ammonium nitrate with a molal concentration of 2.480 m. what are...

given an aqueous solution of ammonium nitrate with a molal concentration of 2.480 m. what are the mole fractions of ammonium nitrate and water?

Expert Solution

molality = weight of substance*1000/gram molar mass * weight of solvent in gm

assume weight of solvent(H2O) = 1000gm

2.480 = weight of substance*1000/80*1000

weight of substance = 2.480*80 = 198.4gm

no of moles of NH4NO3 n1 = 198.4/80 = 2.48 moles

no of moles of water n2 = 1000/18 = 55.5 moles

mole fraction of NH4NO3 X1 = n1/n1+n2

= 2.48/2.48+55.5

= 2.48/57.98

= 0.0427

mole fraction of H2O X2 = n2/n1+n2

= 55.5/2.48+55.5

= 55.5/57.98

= 0.957

queen_honey_blossom answered 2 years ago

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