Question

Calculate the moles and grams of HCl present in the 6.0 mL of 6.0 M HCl solution you used

Answer 1

Molarity = Moles/Volume of solution in litres

Molarity of HCl = 6.0M (Given)

Volume of solution = 6.0mL or 0.006L (Given) ( 1L =1000mL)

Molarity of HCl = Moles of HCl/Volume of HCl solution in litres

(Molarity of HCl)*(Volume of HCl solution in litre) =Moles of HCl

(6.0)*(0.006) = 0.036 moles

Moles of HCl = 0.036

Molar mass of HCl = 1 + 35.5 = 36.5g/mol

Moles of HCl = 0.036 ( Calculated above)

Mole = Given mass/Molar mass

Moles of HCl = Given mass/Molar mass of HCl

0.036 = Given mass/36.5

0.036*36.6 = Given mass

1.314g = Given mass (Mass corresponding to 0.036 moles)

6.0mL of 6.0M HCl have 0.036 moles of HCl or 1.314g of HCl.