Question
In: Statistics and Probability
A local police chief claims that 42% of all drug-related arrests are never prosecuted. A sample...
A local police chief claims that 42% of all drug-related arrests are never prosecuted. A sample of 600arrests shows that 38% of the arrests were not prosecuted. Using this information, one officer wants to test the claim that the number of arrests that are never prosecuted is less than what the chief stated. Is there enough evidence at the 0.02level to support the officer's claim?
Step 2 of 7:
Find the value of the test statistic. Round your answer to two decimal places.
Solutions
orchestra answered 2 years agoRelated Solutions
A local police chief claims that 42%of all drug-related arrests are never prosecuted. A sample of...
A local police chief claims that 42%of all drug-related arrests
are never prosecuted. A sample of 600arrests shows that 38% of the
arrests were not prosecuted. Using this information, one officer
wants to test the claim that the number of arrests that are never
prosecuted is less than what the chief stated. Is there enough
evidence at the 0.02 level to support the officer's claim?
Step 1 of 7:
State the null and alternative hypotheses.
A local police chief claims that 42%of all drug-related arrests are never prosecuted. A sample of...
A local police chief claims that 42%of all drug-related arrests
are never prosecuted. A sample of 600 arrests shows that 38%of the
arrests were not prosecuted. Using this information, one officer
wants to test the claim that the number of arrests that are never
prosecuted is less than what the chief stated. Is there enough
evidence at the 0.02level to support the officer's claim?
Step 3 of 7:
Specify if the test is one-tailed or two-tailed.
A local police chief claims that 42%of all drug-related arrests are never prosecuted. A sample of...
A local police chief claims that 42%of all drug-related arrests
are never prosecuted. A sample of 600arrests shows that 38%of the
arrests were not prosecuted. Using this information, one officer
wants to test the claim that the number of arrests that are never
prosecuted is less than what the chief stated. Is there enough
evidence at the 0.02level to support the officer's claim?
Step 4 of 7:
Determine the P-value of the test statistic. Round your answer
to four decimal...
A local police chief claims that 76% of all drug-related arrests are never prosecuted. A sample...
A local police chief claims that 76% of all drug-related arrests
are never prosecuted. A sample of 700 arrests shows that 72% of the
arrests were not prosecuted. Using this information, one officer
wants to test the claim that the number of arrests that are never
prosecuted is different from what the chief stated. Is there enough
evidence at the 0.01 level to support the officer's claim? Step 1
of 7 : State the null and alternative hypotheses. Step 2...
A local police chief claims that 76%76% of all drug-related arrests are never prosecuted. A sample...
A local police chief claims that 76%76% of all drug-related
arrests are never prosecuted. A sample of 700700 arrests shows that
72%72% of the arrests were not prosecuted. Using this information,
one officer wants to test the claim that the number of arrests that
are never prosecuted is different from what the chief stated. Is
there enough evidence at the 0.010.01 level to support the
officer's claim?
Step 1 of 7 : State the null and alternative
hypotheses.
Step 2...
In Chicago, one of America’s most violent cities, drug arrests have plummeted 42% in the weeks...
In Chicago, one of America’s most violent cities, drug arrests
have plummeted 42% in the weeks since the city shut down, compared
with the same period last year. Part of that decrease, some
criminal lawyers say, is that drug dealers have no choice but to
wait out the economic slump.
“The feedback I’m getting is that they aren’t able to move, to
sell anything anywhere,” said Joseph Lopez, a criminal lawyer in
Chicago who represents reputed drug dealers.
Overall, Chicago’s...
For a sample of 900 police officers at a local police department, a researcher believes there...
For a sample of 900 police officers at a local police
department, a researcher believes there is a relationship between
“number of arrests per month” and “police use of force.” Using the
following data, test the null hypothesis at the .01 level of
significance that police use of force does not differ by the number
of arrests per month that an officer makes. In so doing, identify:
(1) the research and null hypothesis, (2) the critical value needed
to reject...
2. For a sample of 900 police officers at a local police department, a researcher believes...
2. For a sample of 900 police officers at a local police
department, a researcher believes there is a relationship between
“number of arrests per month” and “police use of force.” Using the
following data, test the null hypothesis at the .01 level of
significance that police use of force does not differ by the number
of arrests per month that an officer makes. In so doing, identify:
(1) the research and null hypothesis, (2) the critical value needed
to...
a) A researcher claims that the mean age of CEOs (chief executive officers) of all corporations...
a) A researcher claims that the mean age of CEOs (chief
executive officers) of all corporations in the United States is
4646 years. A sample of 5050 corporations showed that the mean age
of their CEOs is 48.348.3 years with a standard deviation of 5.55.5
years. Find the pp-value for the test that the mean age of CEOs of
all corporations is different from 4646 years at αα =
0.0020.002.
b) The manager of a bank claims that the mean...
A community psychologist selects a sample of 16 local police officers to test whether their physical...
A community psychologist selects a sample of 16 local police
officers to test whether their physical endurance is better than
the median score of 72. She measures their physical endurance on a
100-point physical endurance rating scale. Performance Scores 87 83
78 74 51 88 84 75 89 82 61 86 76 58 77 80 Based on the data given
above, compute the one-sample sign test at a 0.05 level of
significance. x=
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