In: Statistics and Probability
The mean salary is $60,000. What are the chances of you asking 36 randomly selected graduates what their starting wages were and getting a sample mean of $57,000 or less. Assume the standard deviation was $10, 942
Solution :
Given that,
mean = 
 = 60,000
standard deviation = 
 =10942
n = 36

= 60,000

= 
 / 
n = 10942 
36 = 1823.67
P( 
 - < 57,000 )
P ( 
 - 
/
)
< (57,000 - 60,000/ 1823.67)
P ( z < -3000 / 1823.67 )
P ( z < 1.64 )
=0.0505
Probability = 0.0505