Question
In: Statistics and Probability
Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation Xi Yi...
Assume that the differences are normally distributed. Complete parts (a) through (d) below.
Observation Xi Yi
1 52.0 53.4
2 54.3 53.6
3 49.5 54.1
4 44.0 48.7
5 53.9 53.2
6 50.8 52.3
7 50.9 52.6
8 51.0 53.4
(a) Determine di=Xi-Yi for each pair of data.
Answer: Di 1 2 3 4 5 6 7 8
-1.4 0.7 -4.6 -4.7 0.7 -1.5 -1.7 -2.4
(b) Compute d and sd.
Answer: d=-1.863
sd=2.047
(c) Test if μd<0 at the a=0.05 level of significance.
Answer: Ho:ud=0
H1:ud<0
P-value=_______ (round to 3 decimals places as needed)
Need help finding P-value????
Solutions
Expert Solution
P value = 0.018
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orchestra answered 1 year agoRelated Solutions
Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation Xi Yi...
Assume that the differences are normally distributed. Complete
parts (a) through (d) below.
Observation Xi Yi
1 48.8 51.1
2 47.4 48.7
3 48.2 50.1
4 48.0 52.1
5 48.6 48.5
6 49.8 53.6
7 51.7 52.8
8 54.3 53.5
(a) Determine di = Xi−Yi for each pair of data. (Type integers
or decimals.)
di 1__ 2__ 3__ 4__ 5__ 6__ 7__ 8__
(b)Compute d overbard and sd.
d overbard = __ ?
sd = __?
(c)
Test if μd...
Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation Observation Xi...
Assume that the differences are normally distributed. Complete
parts (a) through (d) below.
Observation
Observation Xi Yi
1 44.0 47.1
2 48.0 49.8
3 45.6 47.9
4 47.7 51.8
5 51.9 51.8
6 47.9 47.8
7 47.1 48.3
8 47.8 49.3
(a) Determine di =Xi-Yi for each pair of data.
Observation 1 2 3 4 5 6 7 8
di
(b) Compute d and s d.
d=
sd=
(c) Test if μd< 0 at the a=0.05 level of...
Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation 1 2...
Assume that the differences are normally distributed. Complete
parts (a) through (d) below. Observation 1 2 3 4 5 6 7 8 Upper X
Subscript i 40.9 50.0 44.6 42.9 47.2 48.7 51.4 50.2 Upper Y
Subscript i 45.6 48.3 46.4 47.8 50.1 50.2 53.2 50.6 (a) Determine
d Subscript i Baseline equals Upper X Subscript i Baseline minus
Upper Y Subscript i for each pair of data. Observation 1 2 3 4 5 6
7 8 di nothing nothing...
Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation 1 2...
Assume that the
differences are normally distributed. Complete parts
(a) through (d) below.
Observation
1
2
3
4
5
6
7
8
Xi
43.4
51.5
44.1
44.4
51.3
42.2
47.7
49.4
Yi
47.6
50.2
48.8
49.5
51.2
45.7
48.3
50.2
(a)
Determine di = Xi − Yi for each pair of data.
Observation
1
2
3
4
5
6 7
di
_________ __________ __________ __________ __________
__________ __________
(Type integers or
decimals.)
(b) Compute d and sd .
d=...
Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation 1 2...
Assume that the differences are normally distributed. Complete
parts (a) through (d) below.
Observation
1
2
3
4
5
6
7
8
Upper X Subscript iXi
52.852.8
44.044.0
45.745.7
41.441.4
47.047.0
47.647.6
50.650.6
46.746.7
Upper Y Subscript iYi
53.253.2
45.745.7
50.550.5
45.545.5
48.648.6
47.947.9
51.351.3
46.646.6
(a) Determine
d Subscript i Baseline equals Upper X Subscript i Baseline minus
Upper Y Subscript idi=Xi−Yi
for each pair of data.
Observation
1
2
3
4
5
6
7
8
di
negative ....
Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation 1 2...
Assume that the differences are normally distributed. Complete
parts (a) through (d) below.
Observation
1
2
3
4
5
6
7
8
Xi
44.9
50.8
45.6
48.1
53.5
50.6
49.9
48.0
Yi
46.2
51.3
48.9
52.8
53.7
52.8
50.3
50.6
(a) Determine di=Xi−Yi for each pair of data.
Observation
1
2
3
4
5
6
7
8
di
(Type integers or decimals.)
(b) Compute d and sd.
(c) Test if μd <0 at the a=0.05 level...
Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation 1 2...
Assume that the differences are normally distributed. Complete
parts (a) through (d) below.
Observation
1
2
3
4
5
6
7
8
Open in StatCrunch
+
Copy to Clipboard
+
Open in Excel
+
Upper X Subscript iXi
46.746.7
47.747.7
45.645.6
50.250.2
48.448.4
50.850.8
47.847.8
48.648.6
Upper Y Subscript iYi
50.150.1
48.448.4
47.347.3
54.554.5
47.947.9
50.950.9
49.649.6
50.350.3
(a) Determine
d Subscript i Baseline equals Upper X Subscript i Baseline minus
Upper Y Subscript idi=Xi−Yi
for each pair of data....
Assume that the differences are normally distributed. Complete parts (a) through (d) below. Observation 1 2...
Assume that the differences are normally distributed. Complete
parts (a) through (d) below. Observation 1 2 3 4 5 6 7 8 Upper X
Subscript i 42.7 51.2 44.4 48.6 50.2 44.9 51.9 43.6 Upper Y
Subscript i 46.6 49.6 48.6 52.7 50.6 47.4 52.4 45.7 (a) Determine
d Subscript i Baseline equals Upper X Subscript i Baseline minus
Upper Y Subscript i for each pair of data. compute d and sd test if
Ud<0 at the 0.05 level of...
Height Y and arm span X are normally distributed with means E(Yi) = 168, E(Xi) =...
Height Y and arm span X are normally distributed with means
E(Yi) = 168, E(Xi) = 165, variances
var(Yi)=21, var(Xi)=28, and covariance
cov(Xi ,Yi)=20 for measurements on the same
individual. The variables are normally distributed, and the values
are independent for distinct individuals.
Find the following probabilities for one individual:
P(Di > 9) =
P(Xi > Yi)
=
P(Xi + Yi >
330) =
Consider now two specific unrelated
individuals named i and j respectively. Compute the following
probabilities:
P(Xi...
Use the sample data and confidence level given below to complete parts a through d. A...
Use the sample data and confidence level given below to complete
parts a through d. A research institute poll asked respondents if
they felt vulnerable to identity theft. In the poll, n=1007 and
x=571 who said yes. Use a 95% confidecne level.
A. find the best point of estimate of the population of portion
p. (Round to three decimal places as needed.)
B. Identify the value of the margin of error E. E= round to four
decimal places as needed....
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