In: Statistics and Probability
Please state the step number next to the answers given, thank you!
An automobile manufacturer claims that their jeep has a 31.9
miles/gallon (MPG) rating. An independent testing firm has been
contracted to test the MPG for this jeep. After testing 16 jeeps
they found a mean MPG of 32.1 with a standard deviation of 1.6. Is
there sufficient evidence at the 0.05 level that the jeeps
outperform the manufacturer's MPG rating? Assume the population
distribution is approximately normal.
Step 1 of 5: State the null and alternative
hypotheses.
Step 2 of 5: Find the value of the test statistic.
Round your answer to three decimal places.
Step 3 of 5: Specify if the test is one-tailed or
two-tailed.
Step 4 of 5: Determine the decision rule for
rejecting the null hypothesis. Round your answer to three
decimal places. (Reject H0 if t>_______)
Step 5 of 5: Make the decision to reject or fail
to reject the null hypothesis.
Solution :
= 31.9
=32.1
s =1.6
n = 16
This is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 31.9
Ha : 31.9
Test statistic = z
= ( - ) / s / n
= (32.1-31.9 ) / 1.6 / 16
= 0.500
Test statistic = t = 0.500
P-value = 0.6171
= 0.05
P-value ≥
0.6243 ≥ 0.05
It is observed that ∣t∣=0.5 ≤ tc=2.131, it is then concluded that the null hypothesis is not rejected
Fail to reject the null hypothesis .
There is insufficient evidence to suggest that