In: Statistics and Probability
Solution :
degrees of freedom = n - 1 = 25 - 1 = 24
t/2,df = t0.025,24 = 2.064
Margin of error = E = t/2,df * (s /n)
= 2.064 * ( 800 / 25)
Margin of error = E = 330.24
The 95% confidence interval estimate of the population mean is,
± E
= 6600 ± 330.24
=( $ 6269.76, $ 6930.24 )