In: Statistics and Probability
(1 point) In 2002 the Supreme Court ruled that schools could require random drug tests of students participating in competitive after-school activities such as athletics. Does drug testing reduce use of illegal drugs? A study compared two similar high schools in Oregon. Wahtonka High School tested athletes at random and Warrenton High School did not. In a confidential survey, 4 of 131 athletes at Wahtonka and 20 of 114 athletes at Warrenton said they were using drugs. Regard these athletes as SRSs from the populations of athletes at similar schools with and without drug testing. (a) You should not use the large-sample confidence interval. Why not? (b) The plus four method adds two observations, a success and a failure, to each sample. What are the sample sizes and the numbers of drug users after you do this? Wahtonka sample size: Wahtonka drug users: Warrenton sample size: Warrenton drug users: (c) Give the plus four 90% confidence interval for the difference between the proportion of athletes using drugs at schools with and without testing. Interval: to
a)
You should not use the large-sample confidence interval because at least one sample has too few success
b)
sample #1 ----->
Wahtonka
sample size, n1=
133
wanhotka drug user= x1=
5
proportion success of sample 1 , p̂1=
x1/n1= 0.0376
sample #2 ----->
Warrenton
second sample size, n2 =
116
warrenton drug user, x2 = 21
proportion success of sample 1 , p̂ 2= x2/n2 =
0.1810
c)
level of significance, α = 0.10
Z critical value = Z α/2 =
1.645 [excel function: =normsinv(α/2)
Std error , SE = SQRT(p̂1 * (1 - p̂1)/n1 + p̂2 *
(1-p̂2)/n2) = 0.0394
margin of error , E = Z*SE = 1.645
* 0.0394 = 0.0648
confidence interval is
lower limit = (p̂1 - p̂2) - E = -0.143
- 0.0648 = -0.2082
upper limit = (p̂1 - p̂2) + E = -0.143
+ 0.0648 = -0.0787
so, confidence interval is (
-0.2082 < p1 - p2 <
-0.0787 )