Question

In: Statistics and Probability

Jane and Leah began arguing about who did better on their tests, but they couldn't decide...

Jane and Leah began arguing about who did better on their tests, but they couldn't decide who did better given that they took different tests. Jane took a test in English and earned a 70.5, and Leah took a test in Math and earned a 68.1. Use the fact that all the students' test grades in the English class had a mean of 75.9 and a standard deviation of 11.8, and all the students' test grades in Math had a mean of 66.5 and a standard deviation of 9.8 to answer the following questions.

a) Calculate the z-score for Jane's test grade.
z= [Round your answer to two decimal places.]


b) Calculate the z-score for Leah's test grade.
z= [Round your answer to two decimal places.]


c) Which person did relatively better?

  • Jane
  • Leah
  • They did equally well.

Solutions

Expert Solution

Question (a)

Jane took a test in English and earned a 70.5

the students' test grades in the English class had a mean of 75.9 and a standard deviation of 11.8

So = 75.9

= 11.8

X = 70.5

z-score = (X - ) /

= (70.5 - 75.9) / 11.8

= -5.4 / 11.8

= -0.45763

= -0.46 rounded to 2 decimal places

So z-score for Jane's test grade = -0.46

Question (b)

Leah took a test in Maths and earned a 68.1

the students' test grades in the Maths class had a mean of 66.5 and a standard deviation of 9.8

So = 66.5

= 9.8

X = 68.1

z-score = (X - ) /

= (68.1 - 66.5) / 9.8

= 1.6 / 9.8

= 0.163265

= 0.16 rounded to 2 decimal places

So z-score for Leah's test grade = 0.16

Question (c)

Since the z-score of Leah's is more than that of Jane's, Leah did relatively better

So Answer is Option B


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