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An object starts at the position 4.8x̂ + -9.7ŷ m, with an initial velocity of 1.5x̂...

An object starts at the position 4.8x̂ + -9.7ŷ m, with an initial velocity of 1.5x̂ + -4.4ŷ m/s. It has an acceleration of -0.152x̂ + 0.686ŷ m/s2. After 2.31 s, what is its speed? Report your result in SI units, rounded to one decimal place.

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Expert Solution

We can see that particle is moving in +ve x axis and in the -ve y axis. So we see the component of acceleration in +ve x direction and -ve y direction. We see that there is deceleration in both directions +ve x as well as -ve y. So velocity components in these directions expected to be decrease. We have then write Newton's equation of motion for both components separately. You follow the solution for further details and if you have any doubt, feel free to ask in the comments.

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genius_generous answered 1 year ago
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