Question

The mean cleanup and redecorating time for a one-bedroom student apartment at campus Housing is 10 hours. The time for the cleanup and redecorating process follows the normal distribution. The campus Housing administration instituted a “fee and fine system” that encourages students to clean their apartments when they vacate them. This should shorten the cleanup and redecorating time. A sample of 23 apartments had a mean cleanup and redecorating time of 9.35 hours with a standard deviation of 1.83 hours. Does use of the “fee and fine system” decrease the cleanup and redecorating time? Follow a hypothesis testing procedure using the 0.05 significance level. a. State the null and alternate hypotheses

H0:________________________________________________________________

H1:________________________________________________________________

b. What is the level of significance? b.

c. What is the value of the test statistic? c.

d. Compute the p-value d.

e. What is your decision regarding the null hypothesis? Interpret the result.

__________________________________________________________________________________

__________________________________________________________________________________  

Answer 1

using excel>addin>phstat>one sample test

we have

t Test for Hypothesis of the Mean
Data
Null Hypothesis                m=	10
Level of Significance	0.05
Sample Size	23
Sample Mean	9.35
Sample Standard Deviation	1.83
Intermediate Calculations
Standard Error of the Mean	0.3816
Degrees of Freedom	22
t Test Statistic	-1.7034
Lower-Tail Test
Lower Critical Value	-1.7171
p-Value	0.0513
Do not reject the null hypothesis

a. State the null and alternate hypotheses

H0:u=10

H1:u<10 ( one-tailed )

b. the level of significance is 0.05

c) the value of the test statistic is -1.7034

d) the p-value .0.0513

e. since p-value is greater than 0.05 so do not reject the null hypotheis. we do not have sufficient evidence to conclude that use of the “fee and fine system” decrease the cleanup and redecorating time