In: Economics
If Bob buys a backhoe for $100,000, which has a maintenance cost of $2000/yr that will increase $1,000 per year after year 5, has a required rebuild of its hydraulic system at year 6 that costs $12,000, and then he sells it for $20,000 after 10 years, what is the life cycle cost of his backhoe if the interest rate is 3% per year. PLEASE INCLUDE A CASH FLOW DIAGRAM or I will not rate!! Thank you.
Using Excel
Year | Initial cost | Rebuild req | Annual cost | Resale value | Net Cash flow | Discount factor | Present value |
0 | -100000 | -100000 | 1.00000 | -100000.00 | |||
1 | -2000 | -2000 | 0.97087 | -1941.75 | |||
2 | -2000 | -2000 | 0.94260 | -1885.19 | |||
3 | -2000 | -2000 | 0.91514 | -1830.28 | |||
4 | -2000 | -2000 | 0.88849 | -1776.97 | |||
5 | -2000 | -2000 | 0.86261 | -1725.22 | |||
6 | -12000 | -3000 | -15000 | 0.83748 | -12562.26 | ||
7 | -4000 | -4000 | 0.81309 | -3252.37 | |||
8 | -5000 | -5000 | 0.78941 | -3947.05 | |||
9 | -6000 | -6000 | 0.76642 | -4598.50 | |||
10 | -7000 | 20000 | 13000 | 0.74409 | 9673.22 | ||
Present value | -123846.37 |
Life cycle cost = 123846
Cash Flow diagram
Showing formula in excel
Year | Initial cost | Rebuild req | Annual cost | Resale value | Net Cash flow | Discount factor | Present value |
0 | -100000 | =B18+C18+D18+E18 | =1/1.03^A18 | =F18*G18 | |||
1 | -2000 | =B19+C19+D19+E19 | =1/1.03^A19 | =F19*G19 | |||
2 | -2000 | =B20+C20+D20+E20 | =1/1.03^A20 | =F20*G20 | |||
3 | -2000 | =B21+C21+D21+E21 | =1/1.03^A21 | =F21*G21 | |||
4 | -2000 | =B22+C22+D22+E22 | =1/1.03^A22 | =F22*G22 | |||
5 | -2000 | =B23+C23+D23+E23 | =1/1.03^A23 | =F23*G23 | |||
6 | -12000 | =D23+(-1000) | =B24+C24+D24+E24 | =1/1.03^A24 | =F24*G24 | ||
7 | =D24+(-1000) | =B25+C25+D25+E25 | =1/1.03^A25 | =F25*G25 | |||
8 | =D25+(-1000) | =B26+C26+D26+E26 | =1/1.03^A26 | =F26*G26 | |||
9 | =D26+(-1000) | =B27+C27+D27+E27 | =1/1.03^A27 | =F27*G27 | |||
10 | =D27+(-1000) | 20000 | =B28+C28+D28+E28 | =1/1.03^A28 | =F28*G28 | ||
Present value | =SUM(H18:H28) |