In: Statistics and Probability
A researcher measures the relationship between the number of interruptions during a class and time spent "on task" (in minutes). Answer the following questions based on the results provided.
Number of Interruptions - 9, 4, 6,3
Time Spent "On Task"- 18, 38, 17, 32
Part (a) Compute the Pearson correlation coefficient. (Round your answer to three decimal places.)
Part (b) Multiply each measurement of interruptions times 3 and recalculate the correlation coefficient. (Round your answer to three decimal places.)
Part (c) Divide each measurement in half for time spent "on task" and recalculate the correlation coefficient. (Round your answer to three decimal places.
Part (a)
Pearson correlation coefficient : r
x: Number of Interruptions
y: Time Spent "On Task"
x | y | xy | x2 | y2 | |
9 | 18 | 162 | 81 | 324 | |
4 | 38 | 152 | 16 | 1444 | |
6 | 17 | 102 | 36 | 289 | |
3 | 32 | 96 | 9 | 1024 | |
Total | =22 | =105 | =512 | =142 | =3081 |
Pearson correlation coefficient : r = -0.793
Part (b) Multiply each measurement of interruptions times 3 and recalculate the correlation coefficient. (Round your answer to three decimal places.)
x | y | xy | x2 | y2 | |
9*3=27 | 18 | 486 | 729 | 324 | |
4*3=12 | 38 | 456 | 144 | 1444 | |
6*3=18 | 17 | 306 | 324 | 289 | |
3*3=9 | 32 | 288 | 81 | 1024 | |
Total | =66 | =105 | =1536 | =1278 | =3081 |
Pearson correlation coefficient : r = -0.793
Part (c) Divide each measurement in half for time spent "on task" and recalculate the correlation coefficient. (Round your answer to three decimal places.
x | y | xy | x2 | y2 | |
9 | 18/2=9 | 81 | 81 | 81 | |
4 | 38/2=19 | 76 | 16 | 361 | |
6 | 17/2=8.5 | 51 | 36 | 72.25 | |
3 | 32/2=16 | 48 | 9 | 256 | |
Total | =22 | =52.5 | =256 | =142 | =770.25 |
Pearson correlation coefficient : r = -0.793