Assuming you use 2.5 g vanillin and 5.0 mL of a 3.42 M NaBH4 solution, what...

Assuming you use 2.5 g vanillin and 5.0 mL of a 3.42 M NaBH4 solution, what is the theoretical yield of vanillyl alcohol in moles? in grams?

Solutions

Expert Solution

C8H8O3 + NaBH4 -------> C8H10O3

no of moles of vanilin = W/G.M.Wt

= 2.5/152 = 0.0164 moles

no of moles of NaBH4 = molarity * volume in L

= 3.42*0.005 = 0.0171moles

limiting reagent is vanillin

1 mole of vaniline react with NaBH4 to gives 1 mole of vanilly alcohol

0.0164 moles of vaniline react with NaBH4 to gives = 1*0.0164 moles of vanilly alcohol

mass of vanilly alcohol = no of moles * gram molar mass

= 0.0164*154 = 2.525g of vanilly alcohol

queen_honey_blossom answered 1 year ago

Next > < Previous

Related Solutions

What should be the ph of a solution of 5.0 ml of 0.1 M acetic acid...

What should be the ph of a solution of 5.0 ml of 0.1 M acetic acid and 5.0ml of 0.1M sodium acetate and 40.0ml h20? please show steps

You need 700. mL of a 5.0 % (m/v) glucose solution. If you have a 29...

You need 700. mL of a 5.0 % (m/v) glucose solution. If you have a 29 % (m/v) glucose solution on hand, how many milliliters of this solution do you need?

An aqueous solution is 2.00 M urea. The density of the solution is 1.029 g/ml. What...

An aqueous solution is 2.00 M urea. The density of the solution is 1.029 g/ml. What is the molality concentration of urea in the solution?

Assuming that you start with 2.00 g of sodium benzoate and 5 mL of 3 M...

Assuming that you start with 2.00 g of sodium benzoate and 5 mL of 3 M HCl, how many molar equivalents of HCl are you using? Use two decimal places.

Given 2.5 M HNO2 , 5.0 M NaOH, and DI water, what are the volumes necessary...

Given 2.5 M HNO2 , 5.0 M NaOH, and DI water, what are the volumes necessary to create 500 mL of 1.56 M, pH 4.5, nitrous acid buffer. (Ka of HNO2 = 4.0 x 10-4). [step by step solution please]

A 280.0 −mL buffer solution initially contains 2.5×10−2 M of HCHO2 and 2.5×10−2 M of NaCHO2....

A 280.0 −mL buffer solution initially contains 2.5×10−2 M of HCHO2 and 2.5×10−2 M of NaCHO2. a,) In order to adjust the buffer pH to 4.10, should you add NaOH or HCl to the buffer mixture? The answer is: NaOH b.) What mass of the correct reagent should you add?

(a) 3.25 M NaCl solution (density of solution = 1.08 g/mL)

Calculate the molality of each of the following aqueous solutions. (a) 3.25 M NaCl solution (density of solution = 1.08 g/mL) m (b) 51.4 percent by mass KBr solution m

After mixing 5.00 mL of the 5.0×10–5 M crystal violet solution with 5.00 mL of 0.20...

After mixing 5.00 mL of the 5.0×10–5 M crystal violet solution with 5.00 mL of 0.20 M NaOH, what is the concentration of crystal violet and hydroxide ions in the solution at the start of the reaction? Is it a reasonable assumption that the concentration of OH– is much greater than that of CV+? Why is this an important assumption? Explain.

once vanillin has reacted with NaOH and NaBH4, why can you only add enough HCl to...

once vanillin has reacted with NaOH and NaBH4, why can you only add enough HCl to make the pH go down to 6? what would occur mechanistically if enough HCl (too much) was added to make the pH go down to 1?

Buffer Solution from Strong Base and Weak Acid Solution= 30.0 mL of 1.0 M CH3COOH 5.0...

Buffer Solution from Strong Base and Weak Acid Solution= 30.0 mL of 1.0 M CH3COOH 5.0 mL of 1.0 M NaOH 1. Calculate the total volume. 35 mL 2. What is the concentration of acetic acid in this solution after mixing? (include units) 3. What is the concentration of sodium hydroxide in this solution after mixing (include units) 4. Calculate the expected pH of this buffer solution. 5. Measured pH of this buffer solution. 3.89

Subjects