In: Economics
Suppose you have the following data.
| 
 Year  | 
 # New Homes Sold (1000s)  | 
 Conventional Mortgage Interest Rate  | 
| 
 1995  | 
 667  | 
 7.93  | 
| 
 1996  | 
 757  | 
 7.81  | 
| 
 1997  | 
 804  | 
 7.6  | 
| 
 1998  | 
 886  | 
 6.94  | 
| 
 1999  | 
 880  | 
 7.44  | 
Let H be the number of new homes sold and let M be the conventional mortgage interest rate.

Sample mean = sum of all units / Total number of units
Sample mean of H = 3994/5 = 798.8
Sample mean of M = 37.72/5= 7.544
The formula for Sample variance is 
Where X is the value of the unit
Xbar is the mean
N is the sample size

Sample variance of H = 33342.8/ (5-1) = 8335.7
Sample variance of M = 0.5959/4 = 0.148975
Sample covariance


Covariance = -120.1992/4 = 30.0498
H is independent
and M is dependent
The Line will look like this
M = a +bH
b = 
= -120.1992/ 33342.8= -0,0036
a = Mbar - bHbar
= 7.544 - (-0.0036)* 798.8
= 10.41
The linear regression is
M = 10.41 -0.0036H
Based on the regression equation a 1 unit change in H produces a negative effect of 0.0036 in M.
It has a negative effect.