Question

In: Biology

The undigested antibodies and pepsin digested antibodies were tested for haemagglutination. In the haemagglutination assay, the...

The undigested antibodies and pepsin digested antibodies were tested for haemagglutination. In the haemagglutination assay, the titre for undigested antibodies is 8 and pepsin digested antibodies is 4. why pepsin digested abs has lower titre compared to undigested abs. State 2 reason.

Solutions

Expert Solution

What is a haemagglutination test?

This assay uses the ability of viruses t bind with the RBC with their specific proteins. Thus by analyzing the reaction made on RBC, we can quantify the amount of virus present in the sample. If a person is affected with the virus, the virus form lattices and the blood seems agglutinated. By analyzing the presence of agglutination up tp which dilution gives the amount of virus present. If the virus is not present in the sample, then no lattice is formed. The unit used to evaluate viral quantity is HAU. The reciprocal of endpoint value is called haemagglutination titre (HA titre).

· If the virus is too many in the sample, then the antibody cannot interact with all viruses. Thus the virus interact with RBC and form agglutination in higher dilutions.

· If virus is too low, then antibody will interact with viral antigen and no agglutination is formed with RBC.

The endpoint dilution upto which virus can form agglutination with RBC depends on the viral quantity and also to the efficiency of the antibody present.

Antibody digestion and its advantages?

Digested antibodies have many advantages over undigested antibodies. They are,

· Fc interactions are reduces as it is cleaved which may make non specific interactions which alter the result.

· Fab can efficiently bind to the antigen.

· Has lower immunogenicity than undigested antibodies.

Pepsin is a non-specific endonuclease that cleaves antibodies. It forms 2 Fab fragments. Its advantage is that its binding site is always exposed. So it can bind more effectively.

Thus , the undigested antibody is less efficient that it interact with less amount of virus and thus virus can form agglutination with RBC in more dilutions. But, pepsin digested antibody is more efficient that it can bind with more virus and thus very less amount of virus can interact with RBC and form agglutination.

That’s why, undigested antibody having sample showed agglutination upto 1/8 dilution and gave 8HA titre. But digested antibody showed endpoint in the ¼ dilution. Thus had a HA titre of 4.

This is just about the binding efficiency of antibody and the viral quantity remains more or less the same.


Related Solutions

Papain and pepsin are not the only enzymes that can digest antibodies. Find one example of...
Papain and pepsin are not the only enzymes that can digest antibodies. Find one example of another enzyme that can digest antibodies and answer the following. (~150-200 words total) Describe any similarities or differences in the theoretical antibody fragments generated using this enzyme as compared to pepsin and papain. Use a figure to support your answer. What results would you expect to see in a haemagglutination assay and on non-reducing and reducing SDS-PAGE gels after digesting rabbit anti-SRBC IgG using...
An antibody titer was done on a patient and antibodies ___________ were found to be in...
An antibody titer was done on a patient and antibodies ___________ were found to be in large numbers compared to IgG. This tells us that the patient had ___________ infection.
Suppose you were using a direct hemagglutination assay as a way to measure the amount of...
Suppose you were using a direct hemagglutination assay as a way to measure the amount of an antigen that causes red blood cell clumping. Describe how you would report the results as a titer, and also describe how you could go from this semi-quantitative measure to an absolute quantitation using a standard curve.
Tube No. Digestion (Yes or No) Color Change 1 (EW+Pepsin+Water) No Cloudy, sedimentation 2 (EW+Pepsin+HCl) Yes...
Tube No. Digestion (Yes or No) Color Change 1 (EW+Pepsin+Water) No Cloudy, sedimentation 2 (EW+Pepsin+HCl) Yes Clear, little or no sediment 3 (EW+Pepsin+HCl; in cold) Some digestion Clear, more sedimentation 4 (EW+Boiled Pepsin+HCl) No digestion A lot more sedimentation 5 (EW+Water+HCl) No digestion Cloudy, sedimentation 6 (EW+Pepsin+NaOH) No digestion No sediment; pinkish clear EW = Egg White What do you suppose is the pH of saliva? 2. What do you think will happen to the activity of salivary amylase in...
By Hand: Subjects were trained to respond to a 12-inch visual stimulus and then were tested...
By Hand: Subjects were trained to respond to a 12-inch visual stimulus and then were tested on stimuli of different sizes (9, 10, 11, 12, 13, 13, 14, and 15 inches). The response measure was the degree to which the subjects responded on the first test trial. There were n = 14 subjects in each group. The means for the a = 7 groups are as follows: 9 in      10 in    11 in    12 in    13 in    14 in   ...
A group of 20 prisoners in a particular cellblock were tested on their knowledge of the...
A group of 20 prisoners in a particular cellblock were tested on their knowledge of the rules of the institution. The marks (out of a possible score of 70) were as follows: 31, 28, 27, 19, 18, 18, 41, 0, 30, 27, 27, 36, 41, 64, 27, 39, 20, 28, 35, 30. a) Calculate the range, variance and standard deviation for these data. b) Remove the largest and smallest scores. Re-calculate the range, variance and standard deviation. c) Compare the...
Nine boys and ten girls were tested to determine if there is a difference in the...
Nine boys and ten girls were tested to determine if there is a difference in the average number of days that the child can survive without Internet. The boys averaged 11 days with a standard deviation of 2 days while the girls averaged 13 days with a standard deviation of 3 days. What can be concluded? (Use alpha=0.05).
If you were to have completed the experiment using the Tube Formation Assay technique, what would...
If you were to have completed the experiment using the Tube Formation Assay technique, what would have been some of the expected results and what would have been some of the potential difficulties you might have encountered during the protocol?
1. When an individual receives antibodies that were produced by another person, or animal, providing short...
1. When an individual receives antibodies that were produced by another person, or animal, providing short lived or temporary immunity, that is referred as: active immunity humoral immunity immunosuppression passive acquired immunity immunocompetence 2.  A method to artificially induce an immune response to an infectious disease is: immunity resistance antitoxin vaccination conjugation 3. It is sometimes difficult to produce an immunization against certain pathogens because   they frequently change their molecular protein coat.  This is called: protective antibodies antigenic variation attenuation hypergammaglobulinemia artificial...
Two types of solutions, A and B, were tested for their pH (degree of acidity of...
Two types of solutions, A and B, were tested for their pH (degree of acidity of the solution). Analysis of 6 samples of A showed a mean pH of 6.72 with a standard deviation of 0.024. Analysis of 5 samples of B showed a mean pH of 6.49 with a standard deviation of 0.032. Using a 0.05 significance level, determine whether the two types of solutions have different pH values.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT