What is the molar solubility of CaF2 in 0.10 M NaF solution 25 degrees C? The...

What is the molar solubility of CaF₂ in 0.10 M NaF solution 25 degrees C?

The K_sp for CaF₂ is 3.4x10^-11.

The answer is 3.4x10^-9 M. Please explain how to get to that answer. Thank you!

Expert Solution

CaF2 -----------> Ca⁺² + 2F^-

I 0 0.1

C +x +2x

E +x 0.1+2x

Ksp = [Ca⁺²][F^-]²

3.4*10^-11 = x*(0.1+2x)²

3.4*10^-11 = x(0.1+2x)²

x= 3.39*10^-9

[Ca⁺²] = x = 3.39*10^-9 M = [CaF2]

queen_honey_blossom answered 1 year ago

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