The hydrolysis of 1-chloro-1-methyl cylcoheptane in 80% ethanol follows a first order rate equation. The values...

The hydrolysis of 1-chloro-1-methyl cylcoheptane in 80% ethanol follows a first order rate equation. The values of the specific reaction rate constants are:

temp/C	0	25	35	45
k/s^-1	1.06x10^-5	3.19x10^-4	9.86x10^-4	2.92x10^-3

1. Plot Ln(k) against 1/T

2. Calculate the activation energy

3. Calculate the pre-exponential factor

Solutions

Expert Solution

K = A e^-Ea/RT

lnK = lnK-Ea/RT

lnK = -Ea/RT +lnK

Y = mx+C

Plot Ln(k) against 1/T. A straight line does not passed through origine.Negative slope⁴

logk2/K1 = Ea/2.303R [1/T1 --1/T2]

log3.19*10^-4/1.06*10^-5 = Ea/2.303*8.314 [1/273 - 1/298]

1.4784*19.147 = Ea*(0.00366-0.003355)

Ea = 28.306/0.000305 = 92806.55Joules = 92.80655KJ

3.K = Ae^-Ea/RT

1.06*10^-5 = A e^-92806.55/8.314*273

1.06*10^-5 = Ae-40.88

1.06*10^-5 = A*1.76*10^-18

A = 1.06*10^-5/1.76*10^-18 = 6.02*10¹² htz

queen_honey_blossom answered 1 year ago

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