Question

In: Chemistry

1.What is the coordination number for each of the following complexes? [Co(NH3)4Cl2]+ [Pb(EDTA)]2? [Cu(NH3)4]2+ [Ag(NH3)2]NO3 2.What...

1.What is the coordination number for each of the following complexes?

[Co(NH3)4Cl2]+

[Pb(EDTA)]2?

[Cu(NH3)4]2+

[Ag(NH3)2]NO3

2.What is the charge on each of the following complex ions?

hexaaquachromium(II), [Cr(H2O)6]?

tris(carbonato)ferrate(III), [Fe(CO3)3]?

diaquatetrabromovanadate(III), [V(H2O)2Br4]?

3.What is the oxidation number of the central metal ion in each of the following complexes?

[NiCl2Br2]2?

[Fe(H2O)2(NH3)4]3+

Na[Rh(CN)2]

Expert Solution

(1) NH₃ , Cl^- are mono dentate ligands & EDTA is a hexadentate ligand

To know the coordination number of a metal ion we have to identify the number of ligands present around the central metal in the complex that is which are in the square brakets.

[Co(NH₃)₄Cl₂]⁺ --- Here 4 NH₃ & 2 Cl^- are present , a total of 4+2 = 6 is the coordination number

[Pb(EDTA)]²⁺ --- Here 1 EDTA is presentwhich is a hexadentate ligand so 6 is the coordination number

[Cu(NH₃)₄]²⁺ --- Here 4 NH₃ are present , a total of 4 is the coordination number

[Ag(NH₃)₂]NO₃ --- Here 2 NH₃ , 2 is the coordination number

(2)H₂O --- neutral ligand : CO₃^2- ----- bidantate ligand : Br^- ---- monodentate ligand

hexaaquachromium(II), [Cr(H₂O)₆]?

since the oxidation state of Cr is II & H₂O is a neutral ligand, the charge of the complex becomes +2+(6x0)= +2

Since the oxidation states of the complex is equal to the oxidation state of the metal ions & the ligands.

tris(carbonato)ferrate(III), [Fe(CO₃)₃]?

since the oxidation state of Fe is III & CO₃^2- is a bidantate ligand , the charge of the complex becomes +3+(3x(-2))= -3

diaquatetrabromovanadate(III), [V(H₂O)₂Br₄]?

since the oxidation state of V is III & H₂O is a neutral ligand& Br^- is a monodantate ligand , the charge of the complex becomes +3+(2x0)+(4x(-1)) = -1

(3)The sum of the oxidation state of the metal ion & the ligands present in the complex is equal to the charge on that complex.

Let a be the oxidation state of metal in each complex

[NiCl₂Br₂]^2- Cl^- & Br^- are monodentate ligands

x +(2x(-1))+(2x(-1))= -2

x = +2

[Fe(H₂O)₂(NH₃)₄]³⁺ H₂O & NH₃ are neutral ligands

x +(2x0)+(4x0)= +3

x = +3

Na[Rh(CN)₂] CN^- is a monodentate ligand

The oxidation sate of Na is +1

+1 +[x +(2x(-1))]= 0

x = +1

queen_honey_blossom answered 1 year ago

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