Name the complex ion [Cu(NH3)2(H2O)4]2+. The oxidation number of copper is +2.

Solutions

Expert Solution

queen_honey_blossom answered 1 year ago

Next > < Previous

Related Solutions

What is the coordination number for each of the following complexes or compounds? [Co(NH3)4(H2O)2]3+[Co(NH3)4(H2O)2]3+ [Mg(EDTA)]2−[Mg(EDTA)]2− [Cu(NH3)4]2+[Cu(NH3)4]2+...

What is the coordination number for each of the following complexes or compounds? [Co(NH3)4(H2O)2]3+[Co(NH3)4(H2O)2]3+ [Mg(EDTA)]2−[Mg(EDTA)]2− [Cu(NH3)4]2+[Cu(NH3)4]2+ [Ag(NH3)2]NO3[Ag(NH3)2]NO3 Enter the coordination numbers, in the order that the complexes are listed, as four integers separated by commas (e.g., 1,2,3,4). View Available Hint(s) Submit Part B What is the charge on each of the following complex ions? hexaaquamanganese(II), [Mn(H2O)6]?[Mn(H2O)6]? tris(carbonato)cobaltate(III), [Co(CO3)3]?[Co(CO3)3]? amminepentabromoplatinate(IV), [Pt(NH3)Br5]?[Pt(NH3)Br5]? Express the charges numerically, in the order that the complexes are listed, separated by commas. For a nonzero charge, be...

The complex ion Cu(NH3)42 is formed in a solution made of 0.0400 M Cu(NO3)2 and 0.400...

The complex ion Cu(NH3)42 is formed in a solution made of 0.0400 M Cu(NO3)2 and 0.400 M NH3. What are the concentrations of Cu2 , NH3, and Cu(NH3)42 at equilibrium? The formation constant*, Kf, of Cu(NH3)42 is 1.70 × 1013.

The complex ion Cu(NH3)42 is formed in a solution made of 0.0200 M Cu(NO3)2 and 0.400...

The complex ion Cu(NH3)42 is formed in a solution made of 0.0200 M Cu(NO3)2 and 0.400 M NH3. What are the concentrations of Cu2 , NH3, and Cu(NH3)42 at equilibrium? The formation constant*, Kf, of Cu(NH3)42 is 1.70 × 1013.

The complex ion Cu(NH3)42 is formed in a solution made of 0.0400 M Cu(NO3)2 and 0.500...

The complex ion Cu(NH3)42 is formed in a solution made of 0.0400 M Cu(NO3)2 and 0.500 M NH3. What are the concentrations of Cu2 , NH3, and Cu(NH3)42 at equilibrium? The formation constant*, Kf, of Cu(NH3)42 is 1.70 × 1013.

In an excess of NH3(aq), Cu2+ ion forms a deep blue complex ion, Cu(NH3)42+, which has...

In an excess of NH3(aq), Cu2+ ion forms a deep blue complex ion, Cu(NH3)42+, which has a formation constant Kf=5.6×1011. Calculate the concentration of Cu2+ in a solution prepared by adding 4.6×10−3mol of CuSO4 to 0.550 L of 0.37 M NH3. Express your answer using two significant figures.

In an excess of NH3(aq), Cu2+ ion forms a deep blue complex ion, Cu(NH3)42+, which has...

In an excess of NH3(aq), Cu2+ ion forms a deep blue complex ion, Cu(NH3)42+, which has a formation constant Kf=5.6×1011. Calculate the concentration of Cu2+ in a solution prepared by adding 4.6×10−3mol of CuSO4 to 0.480 L of 0.45 M NH3. Express your answer using two significant figures. I am messing up in the steps somewhere and not sure where. Please show work so I can figure out where. TIA

In an excess of NH3(aq), Cu2+ ion forms a deep blue complex ion, Cu(NH3)42+, which has...

In an excess of NH3(aq), Cu2+ ion forms a deep blue complex ion, Cu(NH3)42+, which has a formation constant Kf=5.6×1011. Calculate the concentration of Cu2+ in a solution prepared by adding 4.5×10−3mol of CuSO4 to 0.550 L of 0.40 M NH3. Express your answer using two significant figures.

Consider the insoluble compound copper(II) hydroxide , Cu(OH)2 . The copper(II) ion also forms a complex...

Consider the insoluble compound copper(II) hydroxide , Cu(OH)2 . The copper(II) ion also forms a complex with ammonia . Write a balanced net ionic equation to show why the solubility of Cu(OH)2 (s) increases in the presence of ammonia and calculate the equilibrium constant for this reaction. For Cu(NH3)42+ , Kf = 6.8×1012 . Use the pull-down boxes to specify states such as (aq) or (s). + + K =

Calculate the equilibrium concentrations of NH3, Cu2+, [Cu(NH3)]2+, [Cu(NH3)2]2+, [Cu(NH3)3]2+, and [Cu(NH3)4]2+ in a solution made...

Calculate the equilibrium concentrations of NH3, Cu2+, [Cu(NH3)]2+, [Cu(NH3)2]2+, [Cu(NH3)3]2+, and [Cu(NH3)4]2+ in a solution made by mixing 500.0 mL of 3.00 M NH3 with 500.0 mL of 2.00 x 10-3 M Cu(NO3)2. The sequential equilibria are Cu2+ (aq) + NH3(aq) ⇐⇒ [Cu(NH3)]2+ (aq) K1 = 1.86 x 104 [Cu(NH3)]2+ (aq) + NH3(aq) ⇐⇒ [Cu(NH3)2]2+ (aq) K2 = 3.88 x 103 [Cu(NH3)2]2+ (aq) + NH3(aq) ⇐⇒ [Cu(NH3)3]2+ (aq) K3 = 1.00 x 103 [Cu(NH3)3]2+ (aq) + NH3(aq) ⇐⇒ [Cu(NH3)4]2+ (aq)...

Subjects