In: Physics
A student working in the physics laboratory connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 225 V. Assume a plate separation of d = 1.27 cm and a plate area of A = 25.0 cm2. When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0.
(a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.)
before Qi = ___ pC
after Qf = ___ pC
(b)
Determine the capacitance (in F) and potential difference (in V) after immersion.
Cf = ___ F
ΔVf = ___ V
(c) Determine the change in energy (in nJ) of the capacitor.
ΔU = ___ nJ
(d)
What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 225 V potential difference.
Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.)
before Qi = ___ pC
after Qf = ___ pC
Determine the capacitance (in F) and potential difference (in V) after immersion.
Cf = ___ F
ΔVf = ___ V
Determine the change in energy (in nJ) of the capacitor.
ΔU = ___ nJ