In: Physics
A parallel plate capacitor with plate separation d is connected to a battery. The capacitor is fully charged to Q Coulombs and a voltage of V. (C is the capacitance and U is the stored energy.) Answer the following questions regarding the capacitor charged by a battery. For each statement below, select True or False.
After being disconnected from the battery, inserting a dielectric with κ will increase C.
With the capacitor connected to the battery, inserting a dielectric with κ will decrease U.
After being disconnected from the battery, decreasing d decreases C.
With the capacitor connected to the battery, decreasing d increases U.
After being disconnected from the battery, inserting a dielectric with κ will increase V.
With the capacitor connected to the battery, increasing d decreases Q.
Capacitance of a capacitor without dielectric, C = ε0 A/d
Capacitance of a capacitor with dielectric, C = ε0 KA/d
Where, A-area of the plates, d – plate separation, K- dielectric constant of the medium.
Energy stored in a capacitor, U = ½ CV2
Where V is the potential difference applied to the capacitor.
Capacitance C, pd V and charge Q can be related as C = Q/V
1.capacitance C can be increased by inserting a dielectric .
The statement is True
2. with the capacitor connected to the battery, new capacitance is K times original capacitance and the p.d V between the plates remains the same , the energy stored becomes k times initial energy.
The statement is False
3. a decrease in separation d increases the capacitance C
The statement is False
4. decrease in separation d increases the capacitance C which in turn increases the energy U as V remains the same with the capacitor connected to the battery
The statement is True
5. potential V = Q/C, insertion of dielectric increases C and decreases V when battery is disconnected from the capacitor.
The statement is False
6. with capacitor connected to battery, V remains the same and charge Q = CV. Increasing d decreases C and hence decreases charge Q
The statement is True