Question

In: Statistics and Probability

Using the Sample Hypothesis Test Data and Chi-Square Data with a .05 level of significance, provide...

Using the Sample Hypothesis Test Data and Chi-Square Data with a .05 level of significance, provide a summary report for the Vice President including the following information:

  • Two-Sample Hypothesis Test: Discuss the hypothesis test assumptions and test used. Provide the test statistic and p-value in your response. Evaluate the results of the hypothesis test with the scenario. Provide recommendations for the Vice President.
  • Chi-square Hypothesis Test: Discuss the hypothesis test assumptions and test used. Provide the test statistic and p-value in your response. Evaluate the results of the hypothesis test with the scenario. Provide recommendations for the Vice President.

Scenario

Land and Agua Insurance company has a call center in the Tempe, Arizona. The business was originally established in Phoenix, Arizona in 1972 as a small business and has grown with the population of the city.   The insurance company specialized in bundling cars, off-road vehicles and watercraft such as jet skis and boats. The company has 150,000 clients in Arizona.

Marjorie Jones, Vice President of Operations is concerned with both the customer complaints and the amount of time representatives are taking to resolve the calls. The team is focused on two areas from the project data collection: call time by location and error type by location. The Vice President wants to know if there is a difference in the amount of time it takes to resolve the calls by location; and a relationship between error type and location.

Team Call Time
Uptown 6.67
Uptown 6.67
Uptown 6.67
Uptown 6.67
Uptown 7.18
Uptown 7.18
Uptown 7.18
Uptown 7.18
Uptown 7.18
Uptown 8.21
Uptown 8.21
Uptown 8.72
Uptown 8.72
Uptown 9.23
Uptown 9.23
Uptown 9.23
Uptown 9.23
Uptown 9.76
Uptown 9.76
Uptown 10.27
Uptown 10.27
Uptown 10.27
Uptown 10.27
Uptown 10.27
Uptown 10.78
Uptown 10.78
Uptown 10.78
Uptown 10.78
Uptown 10.78
Uptown 10.78
Uptown 10.78
Uptown 10.78
Uptown 10.78
Uptown 11.81
Uptown 11.81
Uptown 11.81
Uptown 12.32
Uptown 12.32
Uptown 12.32
Uptown 12.32
Uptown 12.84
Uptown 12.84
Uptown 13.35
Uptown 13.35
Uptown 13.86
Uptown 15.92
Uptown 16.43
Uptown 16.95
Uptown 17.46
Uptown 21.00
Uptown 6.16
Uptown 9.23
Uptown 9.75
Uptown 9.84
Uptown 9.99
Uptown 10.23
Uptown 10.55
Uptown 11.11
Uptown 11.29
Uptown 11.29
Uptown 11.80
Uptown 11.80
Uptown 11.80
Uptown 12.32
Uptown 12.32
Uptown 12.32
Midtown 12.32
Midtown 12.32
Midtown 12.32
Midtown 12.32
Midtown 12.84
Midtown 12.84
Midtown 12.84
Midtown 12.84
Midtown 13.35
Midtown 13.35
Midtown 13.86
Midtown 13.86
Midtown 14.38
Midtown 14.38
Midtown 14.38
Midtown 14.38
Midtown 14.38
Midtown 14.89
Midtown 14.89
Midtown 14.89
Midtown 15.41
Midtown 15.41
Midtown 15.92
Midtown 16.43
Midtown 16.95
Midtown 17.46
Midtown 17.97
Midtown 18.49
Midtown 18.49
Midtown 18.49
Midtown 19.00
Midtown 19.51
Midtown 20.03
Midtown 20.03
Midtown 5.39
Midtown 5.39
Midtown 5.39
Midtown 5.39
Midtown 5.91
Midtown 5.91
Midtown 5.91
Midtown 5.91
Midtown 5.91
Midtown 6.93
Midtown 6.93
Midtown 7.45
Midtown 7.45
Midtown 7.96
Midtown 7.96
Midtown 7.96
Midtown 7.96
Midtown 8.47
Midtown 8.47
Midtown 8.47
Midtown 8.99
Midtown 8.99
Midtown 8.99
Midtown 8.99
Midtown 8.99
Midtown 9.50
Midtown 9.50
Midtown 9.50
Midtown 9.50
Midtown 9.50
Midtown 9.50
Midtown 9.50
Midtown 9.50
Midtown 10.53
Midtown 10.53
Midtown 10.53
Midtown 11.04
Midtown 11.04
Midtown 11.04
Midtown 11.04
Midtown 11.55
Midtown 11.55
Midtown 12.07
Midtown 12.07
Midtown 12.58
Midtown 14.63
Midtown 15.15
Midtown 15.66
Midtown 16.18
Midtown 17.20
Location
Error Type Midtown Uptown Total
Caller Verification 15 12 27
Provided Correct Information 17 11 28
Correct Update 14 16 30
Other Error Types 10 16 26
Total 56 55 111

Solutions

Expert Solution

Let represent uptown and midtown locations.

For testing the difference between call times by location we will use a two-sided t-test for population means.

Uptown Midtown
6.67 12.32
6.67 12.32
6.67 12.32
6.67 12.32
7.18 12.84
7.18 12.84
7.18 12.84
7.18 12.84
7.18 13.35
8.21 13.35
8.21 13.86
8.72 13.86
8.72 14.38
9.23 14.38
9.23 14.38
9.23 14.38
9.23 14.38
9.76 14.89
9.76 14.89
10.27 14.89
10.27 15.41
10.27 15.41
10.27 15.92
10.27 16.43
10.78 16.95
10.78 17.46
10.78 17.97
10.78 18.49
10.78 18.49
10.78 18.49
10.78 19
10.78 19.51
10.78 20.03
11.81 20.03
11.81 5.39
11.81 5.39
12.32 5.39
12.32 5.39
12.32 5.91
12.32 5.91
12.84 5.91
12.84 5.91
13.35 5.91
13.35 6.93
13.86 6.93
15.92 7.45
16.43 7.45
16.95 7.96
17.46 7.96
21 7.96
6.16 7.96
9.23 8.47
9.75 8.47
9.84 8.47
9.99 8.99
10.23 8.99
10.55 8.99
11.11 8.99
11.29 8.99
11.29 9.5
11.8 9.5
11.8 9.5
11.8 9.5
12.32 9.5
12.32 9.5
12.32 9.5
9.5
10.53
10.53
10.53
11.04
11.04
11.04
11.04
11.55
11.55
12.07
12.07
12.58
14.63
15.15
15.66
16.18
17.2

: There is no difference between call times for diff locations ()

VS

: There is difference between call times for diff locations ()

Test Statistic :

Where = 66 = 84

=

= 3.4915

Test Stat =

= -1.820

p-value = 2* P ( < -1.820)

= 2 * P ( > 1.820)

= 0.071 Found using t distribution tables

Since p-value > 0.05

We have insufficient evidence to reject null hypothesis at 5% level. We conclude that there is no difference between the mean call times of locations.

For checking the relationship between error type and location. We are going to use a chi-square test of independence.

There is no relationship between error type and location.

VS

There is a relationship between error type and location.

Test Statistic:

Where Oi and Ei are observed and expected values. The observed are given in the question. We can calculate the expected using the folllowig example.

Eg. Expected for midtown and caller verification cell = =

Location
Error Type Midtown Uptown Total
Caller Verification 13.622 13.378 27
Provided Correct Information 14.126 13.874 28
Correct Update 15.135 14.865 30
Other Error Types 13.117 12.883 26
Total 56 55 111

Individual

Location
Error Type Midtown Uptown
Caller Verification 0.139 0.142
Provided Correct Information 0.585 0.595
Correct Update 0.085 0.087
Other Error Types 0.741 0.754

Test Stat = 3.128

p-value at 0.05 and r (rows) = 4 and c = 2

p-value =

= 0.37

Since p-value > 0.05

There is insufficient evidence to reject the null hypothesis at 5% level of significance. We conclude that there is not relationship between error type and location.


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