Lucas rolls a die 15 times. What is the probability that he gets 3 seven times?

Expert Solution

P(getting 3 in one die) = 1/6

n = 15

This is a binomial distribution.

P(X = x) = 15Cx * (1/6)^x * (1 - 1/6)^15-x

P(X = 7) = 15C7 * (1/6)⁷ * (5/6)⁸ = 0.0053 (ans)

orchestra answered 2 years ago

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