Suppose X~ N (−4,8) Between what x values does about 95% of the data lie?

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Expert Solution

solution:

middle 95% of score is

P(-z < Z < z) = 0.95

P(Z < z) - P(Z < -z) = 0.95

2 P(Z < z) - 1 = 0.95

2 P(Z < z) = 1 + 0. 95= 1.95

P(Z < z) = 1.95/ 2 = 0.975

P(Z <1.96 ) = 0.975

z ±1.96

Using z-score formula

x= z * +

x= -1.96*8+(-4)

x= -19.68

and

x= z * +

x= 1.96*8+(-4)

x= 11.68

orchestra answered 1 year ago

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