In: Statistics and Probability
Find values a and b, such that 95% of the time, X lies between a and b. In other words, find a and b so that P(a <X < b) =:95. Round to 3 decimal places.
PLEASE GIVE EXPLANATION
SOLUTION:
From given data,
Find values a and b, such that 95% of the time, X lies between a and b. In other words, find a and b so that P(a <X < b) =:95.
95% of the time, X lies between a and b
P( - 2 < X < + 2 ) = 95%
95% = 95/100 = 0.95
1 - 0.95 = 0.05
0.05 / 2 = 0.025
at the value of 0.025 the probability (Area under curve) is 1.960 then
P(-1.960 < < 1.960) = 0.95
by comparing with below
P(a < X < b) =0.95
a = -1.960
b = +1.960