How do I solve with TI-83 1. Scores on a test are normally distributed with a...

How do I solve with TI-83

1. Scores on a test are normally distributed with a mean of 63.2 and a standard deviation of 11.7. Find P₁₁, which separates the bottom 11% from the top 89%.

Solutions

Expert Solution

Answer:

Given, = 63.2, = 11.7

P11 is 11th percentile.

For 11th percentile, inv Norm (0.11) = -1.2265

By using TI-83 calculator

P11 = + * invNorm (0.11)

= 63.2 + invNorm (0.11) * 11.7

= 48.84995

orchestra answered 1 year ago

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