Question

1.

DETAILS

MY NOTES

You decide to suspend a 2 kg toy with a string attached to the ceiling for your playful cat. Before the frisky feline starts to play with it, find the tension in the string.

N

2. Suppose a book of mass 4 kg slides down an incline at constant velocity of 2 m/s. The net force on the book is...N

3.

DETAILSMY NOTES

Suppose a book of mass 3 kg slides down an incline at constant acceleration of 1 m/s^2. The net force on the book is

N

4.

DETAILSMY NOTES

Two horizontal forces (F1 and F2) are acting on a 3.7 kg box. Only F1 = 1.7 N is shown in the figure. As shown in the figure, a positive answer for F2 means that it points to the right (negative means it points to the left). Ignore friction. Find F2 when the acceleration of the box is 2 m/s^2.


N

5.

DETAILSMY NOTES

A car of mass 2050 kg traveling at speed 23 m/s crashes in a one dimensional collision into the rear of a slower moving truck of mass  2875 kg traveling at 8.8 m/s in the same direction. If the collision is perfectly inelastic, what is the speed of the combined car and truck after the collision?

m/s



A car of mass 2050 kg traveling at speed 23 m/s crashes in a one dimensional collision into the front of a slower moving truck of mass  2875 kg traveling at 8.8 m/s in the opposite direction. If the collision is perfectly inelastic, what is the velocity of the combined car and truck after the collision?(Take the positive direction to be the initial direction of the car.)

m/s



A car of mass 2050 kg traveling at speed 23 m/s crashes into a truck of mass  2875 kg traveling at 8.8 m/s that falls (for some reason) vertically. If the collision is perfectly inelastic, what is the velocity of the combined car and truck after the collision?(Take the positive direction to be the initial direction of the car.)

m/s

6.

DETAILSMY NOTES

We are in a parallel universe where you have a mass of 70 kg. In these hard times (apparently the Corona virus is here too), you decided to rob a bank and Spiderman caught you. Thats not good. You try to run away. Before Spiderman's spider string catches you, you are traveling at a speed of 4 m/s. The initial attachment of the spider string immediately slows you down to a speed of 1 m/s. You are still running away, albeit slower. What is the magnitude of the impulse you experience from the spider string.  

kg-m/s

7.

DETAILSMY NOTES

You slide your 1.5 kg beverage across the table. Thankfully, it doesn't spill. If the coefficient of kinetic friction between the table and beverage is 0.43, find the magnitude of the acceleration. (As a reminder, magnitude means your answer should be positive.)

m/s^2

8.

DETAILSMY NOTES

A 11 kg package is sliding down a hill with an incline angle of 21 degrees from a horizontal surface. If the package slides down the hill at a constant velocity of 0.9 m/s, find the magnitude of the friction force. Yes, it is possible to solve this problem without the coefficient of kinetic friction; it arguably makes the problem easier. (As a reminder, magnitude means your answer should be positive.)

N

9.

DETAILSMY NOTES

With the exception of gravity and normal force, only the following two forces are acting on a dresser of mass 11 kg moving across a horizontal surface. Vector 1 has a magnitude of 2.6 with an angle from the horizontal of 36. Vector 2 has a magnitude of 2.1 and an angle from the horizontal of 19 degree. Find the acceleration of the dresser.

m/s^2

10.

DETAILSMY NOTES

Cindy who is 58 kg pushes on Joe who is 72 kg. She pushes on Joe with a force of 108 N. With what magnitude of force does Joe push on Cindy during that same push? (As a reminder, magnitude means your answer should be positive.)

N

11.

DETAILSMY NOTES

I lift my physics textbook a height of 1 m. What is the total work done on the book by all forces if I lift the book at a constant velocity of 2.6 m/s. Ignore air resistance.

J

12.

DETAILSMY NOTES

A 1.6 kg ball is held at a height of 1 m above the ground. If it is dropped, what will its kinetic energy be immediately before it hits the ground? You may ignore air resistance.

J

13.

DETAILSMY NOTES

I apply a horizontal force of 159 N to a 1.2 kg box being pushed across a horizontal surface. The coefficient of friction is 0.44. If the box is pushed 0.41 m, what is the work done by friction? Think carefully about what should be the sign of the work too.

J

14.

DETAILSMY NOTES

A treasure slides down a 48 meter tall incline with an incline angle of 3.6 degrees at a constant speed of 0.21 m/s. What is the TOTAL work done on the treasure chest?

J

15.

DETAILSMY NOTES

A 17.5 kg object starts at the top of a 5.4 m tall hill at rest. At the bottom of the hill that it slid down, it has a velocity of 2.5 m/s. What is the work done by friction? (As with the work done by any force, I encourage you to think about what the sign of work done by friction should be when inputting your answer.)

J

16.

DETAILSMY NOTES

My child has left a 3 kg toy on one of the bottom stairs at a height of 1.3 m from the ground. After frustration that my child still hasn't put the toy away, I throw it up the stairs to a height of 3.4 m above the ground. What is the change in the potential energy that the toy experienced due to this throw?

J

17.

DETAILSMY NOTES

A 0.147 kg baseball is traveling at 16.9 m/s towards a baseball hitter. The baseball player hits the ball in the opposite direction from the pitch. The speed of the ball after the hit is 23.9 m/s. If the time period of the ball in contact with the bat is 0.1 seconds, what is the magnitude of the force that the bat puts on the ball?  

N

18.

DETAILSMY NOTES

An object of mass 10 kg has an x component of velocity of 5 m/s and a y component of velocity of 7 m/s. What is the magnitude of the total momentum of the object?  

kgm/s

PLEASE SHOW ALL WORK.

Answer 1

Sol: The tensioin in string T = mg = 2x9.81 = 19.62 N

Sol: Here book is sliding with constant velocity i.e. acceleration is zero hence the net force will be zero.

Sol: Here mass m=3kg and acceleration a = 1m/s^2 Hence net force F = ma = 3x1 = 3N

Sol: Here mass m = 3.7kg andacceleration a=2m/s^2 Hence net force F = ma =3.7x2 = 7.4 N
Now as F1 and F2 are horizontal hence F1 + F2 = 7.4
or F2 = 7.4 - F1 = 7.4 - 1.7 =5.7 N (if F1 and F2 both are in same direction)
or F2-F1 = 7.4 or F2 = 7.4+1.7=9.1N (if F2 is opposit of F1)

Note: Please post other question separately.