Question

Make a phasor diagram for an LRC circuit 5000 Hz if voltage across LC is 4.0 V, voltage across a resistor is 9.0 V, peak current is .09 A, and the phase difference between R to LC is 6.3 radians. I always rate for helpful answers

Answer 1

The phasor diagram is a representation of how voltage changes with current.

Suppose that a current, given by

passes through a circuit containing a resistor, capacitor and inductor.

The voltage across each component will not have the same phase.

• The voltage across resistor will be in phase with current
• The voltage across the capacitor will lag behind voltage by pi/2
• The voltage across the inductor will lead the current by pi/2

The phasor diagram is thus given as shown below.

Here, V_R = 9.0 V

V_LC = V_L +V_C = 4.0 V

The phase angle is +6.3 radian = 360.963 degree, which is equal to 0.963 degrees.

Using

Thus, using this and the above equation for V_LC ,

and

Thus, the phasor diagram will be

(Remember that the diagram is not to scale. The phase angle is almost 1 degree and can not be drawn so that the idea is understood. original diagram will have V_s, much close to the X axis)