In: Economics
Number of bags of chips consumed |
Marginal valuation of a bag of chips |
Number beer cans consumed |
Marginal valuation of beer |
1 |
20 |
1 |
70 |
2 |
14 |
2 |
60 |
3 |
8 |
3 |
40 |
4 |
4 |
4 |
13 |
5 |
0 |
5 |
5 |
Solution:
The optimal commodity bundle to be consumed is where the marginal valuation per dollar price of one good equals the marginal valuation per dollar price of the other good. Also, the chosen bundle must be in the budget of the consumer.
Then, for the given table:
Marginal valuation of bag of chips/price of chips bag equals or is closest to Marginal valuation of beer/price of beer
So,marginal valuations of chips bags per dollar is: 1: 20/2 = 10 ; 2: 14/2 = 7; 3: 8/2 = 4; 4: 4/2 = 2; 0: 0/2 = 0
And for beer is: 1: 70/4= 17.5 ; 2: 60/4=15; 3: 40/4=10; 4 : 13/4 = 3.25; 5 : 5/4 = 1.25
So, clearly the marginal valuation per dollar for each good equals at 1 bag of chips and 3 beers, and the corresponding expense = 2*1 + 4*3 = 2 + 12 = $14
We still have 4 dollars left (18 - 14), so next either two more chips bags or 1 more beer could be taken. Two more chips bags will give a total additional utility of 14 + 8 = 22, while additional beer will give additional utility of 13. So in order to maximize utility, 2 more chips bags should be taken.
Finally, we have the final consumption bundle as: 3 bags of chips and 3 beers (total utility = 20+14+8+70+60+40 = 212).