In: Statistics and Probability
The following data represent the results of an independent-measures experiment comparing three treatment conditions. Use analysis of variance with = .05 to determine whether these data are sufficient to conclude that there are significant differences between the treatments. (Hint: start by filling in the missing values on the table below). Please show all formulas with symbols (and plugin numbers), steps, processes, and calculations for all steps and all parts of all answers.
Treatment 1 | Treatment 2 | Treatment 3 | |
4 | 7 | 6 | |
6 | 5 | 12 | |
4 | 3 | 12 | |
2 | 5 | 6 | N = 12 |
M = 4 | M = 5 | M = 9 | G = |
SS = | SS = | SS = | Ex2 = |
The following table is obtained:
Group 1 | Group 2 | Group 3 | |
4 | 7 | 6 | |
6 | 5 | 12 | |
4 | 3 | 12 | |
2 | 5 | 6 | |
Sum = | 16 | 20 | 36 |
Average = | 4 | 5 | 9 |
∑iXij2= | 72 | 108 | 360 |
St. Dev. = | 1.633 | 1.633 | 3.464 |
SS = | 8 | 8 | 36 |
n = | 4 | 4 | 4 |
G = ( 4 + 5 + 9 ) / 3 = 6
Conclusion
It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that not all 3 population means are equal, at the α=0.05 significance level.